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Ugo [173]
3 years ago
10

Jeremy determines that \sqrt{9} = 9^{\frac{1}{2}} . Part of his work is shown. \sqrt{9} = 3 = 3^1 = 3^{\frac{1}{2}+\frac{1}{2}}

= _________ = 9^{\frac{1}{2}} Which expression or equation should be placed in the blank to correctly complete Jeremy's work?
Mathematics
1 answer:
daser333 [38]3 years ago
7 0

3¹

Step-by-step explanation:

Jeremy determines that \sqrt{9} =9^{\frac{1}{2} }

His work should show \sqrt{9} =3=3^{1} =3^{\frac{1}{2} +\frac{1}{2} } =3^{1} =9^{\frac{1}{2} }

The part that adds  \frac{1}{2} +\frac{1}{2} =1 is missing

Thus two halves equals a whole, then it will be 3¹

Learn More

Indices : brainly.com/question/12720046

Keyword : Expressions, indices

#LearnwithBrainly

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All corresponding sides and angles will be congruent

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How do I solve 0.6(-13k-12)
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Answer:

-7.8k - 7.2

Step-by-step explanation:

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A grocery store sells salmon fillets in package that contains at least 3 fillets of salmon,but no more than 5.which of the follo
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Answer: 18 ≤ 6*S ≤ 30

Where S is the number of salmon fillets in one single package.

Step-by-step explanation:

Let's define S as the number of salmon fillets in one package.

We know that it contains at least 3, and no more than 5, then we can write:

3 ≤ S ≤ 5

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Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?
natima [27]

Answer:

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

Step-by-step explanation:

The question is poorly formatted. The original question is:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

We have:

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7

Open bracket

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 8 as 2^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}

Express 2^3 as 8

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}

Expand each exponent

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}

Split

(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}

Factorize

(8x^3)^ \frac{2}{3} \sqrt{75x^3}  + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}

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