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storchak [24]
4 years ago
10

Subject: Finding Range Using a Graph

Mathematics
1 answer:
grigory [225]4 years ago
5 0

Answer:

4.7

Step-by-step explanation:

The red I think is hinting to the x.

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Jun writes an expression 5(x+2).Then he uses the Distributive property to write the equivalent expression 5x+10. How can he subs
Drupady [299]
I am not sure but I think this is what it means by.
 You can substitute 4 for an example for x.
 5(4+2)          5(4)+10
 5(6)              20+10
 30                    30
5 0
3 years ago
The graph shows the height (h), in feet, of a basketball t seconds after it is shot. Projectile motion formula: h(t) = -16t2 + v
Harlamova29_29 [7]

Answer:

\boxed{h(t)=-16t^2+24t+6}

<h2>Step-by-step explanation: </h2><h2 /><h3>From the statement of the problem we know: </h3>

The graph shows the height (h), in feet, of a basketball t seconds after it is shot. Projectile motion formula:  

h(t)=-16t^2+vt+h_{0}

v = initial vertical velocity of the ball in feet per second

h_{0} = initial height of the ball in feet Complete the quadratic equation that models the situation.

<h3>From the graph we know: </h3>

h(0)=6 \\ \\ \therefore 6=-16(0)^2+v(0)+h_{0} \\ \\ \therefore h_{0}=6

For a quadratic function:

f(x)=ax^2+bx+c \\ \\ \\ The \ vertex \ is: \\ \\ V(-\frac{b}{2a},f(-\frac{b}{2a})) \\ \\ Since: \\ \\ h(t)=-16t^2+vt+6 \ then: \\ \\ a=-16 \\ b=v \\ c=h_{0}=6 \\ \\ So: \\ \\ -\frac{b}{2a}=-\frac{v}{2(-16)}=0.75 \\ \\ \frac{v}{32}=0.75 \\ \\ \therefore v=32(0.75) \ \therefore v=24

 Finally:

\boxed{h(t)=-16t^2+24t+6}

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3 years ago
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maria [59]

Answer:

a

Step-by-step explanation:

6 0
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What is $0.12 in cents?
natka813 [3]

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12 cents

Step-by-step explanation:

7 0
3 years ago
If a and b are real numbers and a&gt;0 and b&gt;0 , then ab ___0
Pepsi [2]

-------------------------------------------------------------------------------------------------------------

Answer:  \textsf{ab} > \textsf{0}

-------------------------------------------------------------------------------------------------------------

Given: \textsf{a} > \textsf{0 and b} > \textsf{0}

Find:  \textsf{ab } \_\_\_ \textsf{ 0}

Solution: Since we know both a and b are positive this means that if they are multiplied against each other they would produce another positive. Therefore, this would cause the statement to be ab > 0.

4 0
2 years ago
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