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velikii [3]
4 years ago
14

Help me and I'll label the first person the brainest

Mathematics
1 answer:
Zina [86]4 years ago
5 0

irrational since Pi as infinity numbers

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I also need help on this one smh
AysviL [449]

Answer:

C. 176.6 Square feet (I think)

Step-by-step explanation:

I tried many different ways and got three of the answers above but I think this is the right one.

The equation to find area of a circular cone base: A= \pi r^2

  1. We are given the diameter (15 Feet) but we need to find the radius. So we use the diameter to radius formula: r = \frac{d}{2}
  2. Plug in numbers: r=\frac{15}{2} ≈ 7.5
  3. Use the Area formula now that you have radius: A=\pi 7.5^2
  4. Solve and get = a = 176.71458676
  5. Looking at the options the closest one to our answer (off by one-tenth) is C.

Sorry if you get this wrong. I tried lol.

7 0
2 years ago
Which intervals are most appropriate for a histogram
Lorico [155]

Answer:

C. 10–15, 15–20, 20–25, 25–30, 30–35

Step-by-step explanation:

5 0
3 years ago
please help i don't understand this one i appreciate anyone who helps :) Solve for x. 7x - 3/8 = 6x -
svet-max [94.6K]

Answer:

x = 3/8

Step-by-step explanation:

6 0
3 years ago
Please answer quickly!
Damm [24]

Answer:

2.57 or 2.5703939893007399

Hope this helped have a good one! :)

6 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
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