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Makovka662 [10]
3 years ago
5

If four times the sum of a number and 5 is divided by 3 , the result is 16

Mathematics
2 answers:
Black_prince [1.1K]3 years ago
6 0

If four times the sum of a number and 5 is divided by 3, the result is 16. Step 1. Let x be the number.

Step 2. Four times the number and 5 is divided by 3

Step 3. The result is 16

Step 4. Multiply by 3 to both sides of equation to get rid of denominator

Step 5. Subtract 20 from both sides of equation

Step 6. Divide by 4 to both sides of equation

Step 7 ANSWER is x=7.

I hope the above steps were helpful.

Dmitrij [34]3 years ago
5 0

Answer: false

Step-by-step explanation:

You need to divide 5 and 3 and you would get 1.6 repeating and then you drop the 4x and you should have gotten 4x plus 1.6 because 1.6 doesn’t have a variable. I hope this made sense.

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Y=6mx-2b what is y equal to ?
Maksim231197 [3]
Hello there.

<span>Y=6mx-2b what is y equal to

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7 0
3 years ago
Who is correct chris or sam
Advocard [28]
Lacey, because you have to do the opposite when you want to get rid of a number. She subtracted 20 because it was originally positive 20. Chris messed up and did not do the opposite, subtraction, and instead he added 20
4 0
3 years ago
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Rewrite the equation B - 7,536 = 2t as a function of t.
pav-90 [236]

Answer:

B = 2t + 7,536

Step-by-step explanation:

B - 7,536 = 2t

Add 7,536 to both sides.

B = 2t + 7,536

8 0
3 years ago
The following data was collected from a simple random sample of a population.
aivan3 [116]

Answer:

C

Step-by-step explanation:

This problem is analogous to the extraction of 6 elements from a total of 10 elements. It's the same if they are marbles, chips, or in this case, people, as here we don't care about the order of the selection as we only are drawing a sample.

Thus, the problem implies solving the amount of possible combinations of 10 people if we take by 6. There is a formula for this and is:

10 C 6 = 10!(6!4!)

If we operate, knowing that for any number x, x!=x*(x-1)*(x-2)*...*1

10 C 6 = 10!(6!4!) = 10*9*8*7*6*...*1 / [(6*5*...*1) * (4*3*2*1)]

10 C 6 = 10*9*8*7*6! / [(6*5*...*1) * (4*3*2*1)]

We have a 6! multiplying and another dividing, so they get eliminated, and as 4*2=8 and 9=3*3

10 C 6 = 10*9*8*7*/ [(4*3*2*1)] = 10*3*3*8*7*/ [(8*3*1)]

We can eliminate the 8s and one of the 3s on the numerator with the one on the denominator:

10 C 6 = 10*3*7*/1 = 210/1= 210

So, option C

5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BQuestion%3A%7D" id="TexFormula1" title="\huge\boxed{Question:}" alt="\huge\b
iragen [17]

The equivalent expression for (x + 4)^5 is x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

The expression is given as:

(x + 4)^5

To expand the expression, we make use of Pascal triangle, where:

5:= 1 5 10 10 5 1

So, we have:

(x + 4)^5 = 1 * x^5 * 4^0 + 5 * x^4 * 4^1  + 10 * x^3 * 4^2 + 10 * x^2 * 4^3 + 5 * x * 4^4 + 1 * x^0 * 4^5

Evaluate the exponents

(x + 4)^5 = 1 * x^5 * 1 + 5 * x^4 * 4 + 10 * x^3 * 16 + 10 * x^2 * 64 + 5 * x * 256 + 1 *1 * 1024

Evaluate the products

(x + 4)^5 = x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

Hence, the equivalent expression for (x + 4)^5 is x^5+ 20x^4+ 160x^3 + 640x^2 + 1280x  + 1024

Read more about binomial expressions at:

brainly.com/question/13602562

7 0
3 years ago
Read 2 more answers
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