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3 years ago

The value of y varies directly with x, and y =-8 when x =2. Write the equation that relates x and y and then find y when x =3.

Mathematics

1 answer:

lesya [120]3 years ago

7 0

I don’t know if this is right but
-4x=y
So if X is 3 then Y would be -12

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The value of n is both 5 times as much as the value of m and 36 more than the value of m. what are the values of n and m? explai

Cloud [144]

I'm in seventh grade. I haven't learned that yet.
try asking your teacher.

8 0

3 years ago

A standard city block in Manhattan is a rectangle measuring 80 m by 270 m. A resident wants to get from one corner of a block to

kondor19780726 [428]

Answer:

68.4 meters shorter

Step-by-step explanation:

ok so you want to compare the distance 80 m + 270 m with the diagonal length.

the diagonal length = root ( 80^2 + 270^2 )

diagonal length = root(6400 + 72900)

diagonal = root(79300) =281.602 m

so.

350 - 281.602 = 68.397 meters about 68.4 meters shorter than walking around

5 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago

Please answer this question as soon as possible

Taya2010 [7]

Answer: The graph is shifted vertically, but not horizontally

Step-by-step explanation:

Since the added constant is outside the x term, the constant will only shift the graph vertically.

6 0

3 years ago

Use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the curves about the given

Fed [463]

See attachment for one such shell. The volume is given by the sum of infinitely many thin shells like this, each with radius $x$ and height determined by the vertical distance between the upper blue curve and the lower orange curve for any given $x$ , i.e. $8e^x-8e^{-x}$ .

The volume is then

$2\pi\displaystyle\int_0^1x\left(8e^x-8e^{-x}\right)\,\mathrm dx=16\pi\int xe^x(e^{2x}-1)\,\mathrm dx=\dfrac{32\pi}9(e^3-4)\approx179.677$

7 0

3 years ago