A line passes through point (-2, 5) and has a slope of 2/3. Points A(x, 3) and B(-2, y) lie on the line. The value of x is____, and the value of y is _____. Please help I've seen this problem on this website before but no one actually answered I know it's probably very simple to get the answer but I don't know how could someone tell me how to or answer it please thanks?
1 answer:
Use the equation y = mx +c y = 2/3x +c Substitute the slope (m) in 5 = 2/3(-2) +c Substitute the point (-2,5) 5 = -4/3 +c Make C the subject c = 19/3 y = 2/3x + 19/3 This is the equation of the line. Next you start subbing the points A and B in separately, using the same equation. Subbing A(x, 3) 3 = 2/3x + 19/3 Make x the subject to find it. -10/3 = 2/3x -5 = x The point A is (-5,3) Subbing B(-2, y) y = 2/3(-2) + 19/3 y is already the subject and you just solve it = -4/3 + 19/3 y = 5 The point B is (-2, 5) <span>I hope this helped you, I have also attached a photo of the written work! I'm also sorry if the answer isn't correct... >-<</span>
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A = arccos [(b² + c² - a²)/(2bc)] = arccos [(13.2² + 15.8² - 7.3²)/(2*13.2*15.8)] = 27.3°
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