Answer:
Step-by-step explanation:
Red:black = 1:1
Red cards = x
Black cards =x
x + x = 48
2x = 48
x = 48/2
x = 24
No. of red cards = 24
No of black cards = 24
Now 8 red cards are removed
So, No. of red cards = 24 - 8 =16
Red: Black = 16:24

Red: Black = 2:3
Answer:
Step-by-step explanation:
<em>(5√3*√3)+(5√3*5)+(-1*√3)+(-1*5) </em>
<em>5*3+25√3-√3-5 </em>
<em>15+24√3-5 </em>
<em>**24√3+10** </em>
<em></em>
<em>Then to solve the second, apply division rules within the radical. This means you can cancel an m^1 and n^4 from the bottom and top of the fraction. This leaves... </em>
<em>3√(88m^19*n^8) </em>
<em>(That might be all you need to do, otherwise you can take the square root of each number in the term giving... </em>
<em>3(√88)*m^9.5*n^4)</em>
<em></em>
<em>Hope I made it clear enough</em>
<em></em>
<em>Please give me Brainliest</em>
Answer:
The first one on top
Step-by-step explanation:
Answer: 20w + 3
———————
10
Step-by-step explanation:
Answer: option A is the correct answer
Step-by-step explanation:
The set of line segments that can be used is the one such that, its longest side is lesser than the semi perimeter,s[s=(a+b+c)/2] of the triangle.
If we apply this condition on the given line segments,
A) 2 cm, 8 cm, and 9 cm
s = (2+8+9)/2 = 9.5
9.5 is greater than 9cm
B) 3 cm, 6 cm, and 2 cm
s = (3+6+2)/2= 5.5
5.5 is lesser than 6. If we go on to look for the area using
Area = √s(s-a)(s-b)(s-c), it would be impossible because we would end up having square root of a negative number.
C) 5 cm, 9 cm, and 3 cm
s = (5+9+3)/2 = 8.5
8.5 is lesser than 9cm
If we go on to look for the area using
Area = √s(s-a)(s-b)(s-c), it would be impossible because we would end up having square root of a negative number.
D) 6 cm, 3 cm, and 10 cm
s = (6+3+10)/2 = 9.5
9.5 is lesser than 10
If we go on to look for the area using
Area = √s(s-a)(s-b)(s-c), it would be impossible because we would end up having square root of a negative number.
So option A is the correct answer