Using the following triangle, what is the secant of angle b?

<img src="https://tex.z-dn.net/?f=4%20%20%5Ccos%2860%20%2B%20%20%5Calpha%20%29%20%20%5Csin%2830%20%2B%20%20%5Calpha%20%29%20%20%

Yuri [45]

Answer:

i am very bad at o math i am only at 8 sorry

Step-by-step explanation:

if you could give me a brainliest.

5 0

3 years ago

What values of a and b would make the equation shown have infinitely many solutions? 3x=ax+b

Wittaler [7]

Infinitely many solutions means that you have the same thing on both sides of the equation no matter what value of x you plug in, right?

We just need both sides to be 3x then, correct?

If a were equal to 3 and b were equal to 0, we'd have

3x = (3)x + 0

Which is essentially 3x = 3x

So that means a = 3 and b = 0 must work!
Let's say x = 5

3(5) = 3(5) + 0

15 = 15 + 0

15 = 15

That means that a = 3 and b = 0 is your final answer :)

7 0

3 years ago

Janet has 120 dollars,. if she saves 20 dollars per week, in how many days will she have 500?

GrogVix [38]

After 28 days she will have 200. every 28 days she saves 80 dollars and after 112 she will have saved 320. She will then be at 460 and need 40 more dollars which is 14 days, and 112 plus 14 is 126 days. Hope that helped

4 0

3 years ago

A baseball hat for $22.90 at 5% sales tax

vovikov84 [41]

I think it's $21.75 with tax

5 0

4 years ago

Read 2 more answers

In a large population, 3% of the people are heroin users. A new drug test correctly identifies users 93% of the time and correct

kari74 [83]

Answer:

(a) The probability tree is shown below.

(b) The probability that a person who does not use heroin in this population tests positive is 0.10.

(c) The probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d) The probability that a randomly chosen person from this population tests positive is 0.1249.

(e) The probability that a person is heroin user given that he/she was tested positive is 0.2234.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is a heroin user

<em>Y</em> = the test is correct.

Given:

P (X) = 0.03

P (Y|X) = 0.93

P (Y|X') = 0.99

(a)

The probability tree is shown below.

(b)

Compute the probability that a person who does not use heroin in this population tests positive as follows:

The event is denoted as (Y' | X').

Consider the tree diagram.

The value of P (Y' | X') is 0.10.

Thus, the probability that a person who does not use heroin in this population tests positive is 0.10.

(c)

Compute the probability that a randomly chosen person from this population is a heroin user and tests positive as follows:

$P(X\cap Y)=P(Y|X)P(X)=0.93\times0.03=0.0279$

Thus, the probability that a randomly chosen person from this population is a heroin user and tests positive is 0.0279.

(d)

Compute the probability that a randomly chosen person from this population tests positive as follows:

P (Positive) = P (Y|X)P(X) + P (Y'|X')P(X')

$=(0.93\times0.03)+(0.10\times0.97)\\=0.1249$

Thus, the probability that a randomly chosen person from this population tests positive is 0.1249.

(e)

Compute the probability that a person is heroin user given that he/she was tested positive as follows:

$P(X|positive)=\frac{P(Y|X)P(X)}{P(positive)} =\frac{0.93\times0.03}{0.1249}= 0.2234$

Thus, the probability that a person is heroin user given that he/she was tested positive is 0.2234.

6 0

3 years ago