Question

Solve (x - 2 < 5) ∩ (x + 7 > 6).

Answer 1

(x - 2 < 5) ∩ (x + 7 > 6)

Let's resolve each one

x - 2 < 5

x < 5 + 2

x < 7

x + 7 > 6

x > 6 - 7

x > -1

So we have 2 conditions: x > -1 and x < 7 plus, we need the values that's equal in x < 7 and x > -1 because we have an intersection

S = {x e R / -1 < x < 7}