What is the solution of (4^3 x 4^-2)^-2?

Mathematics

2 answers:

AlladinOne [14]3 years ago

6 0

Answer:

0.0625

Step-by-step explanation:

In order to find the answer to this question you must use order of operations and realize that with negative exponents instead of multiplying you divide.

$(4^3\times4^{-2})^{2}$

$4^3=4\times4\times4=64$

$4^{-2} =0.0625$

Use PEMDAS:

$64\times0.0625 = 4$

$4^{-2}$

$4^{-2} =0.0625$

$x=0.0625$

Hope this helps.

weqwewe [10]3 years ago

4 0

That is ur answer crack!!! Give me a like

You might be interested in

How are algebraic expressions evaluated using substitution?

Alinara [238K]

Answer:

if you mean like you have a algebraic expression and they give you the values of the variables to substitute into the equation, then you just replace the variable with the value for instance

if x = 5

in the equation x + 3 =

then we would replace x with 5 and get 5 + 3 = 8

Step-by-step explanation:

4 0

3 years ago

Explain how to perform a two-sample z-test for the difference between two population proportions.

Sati [7]

Point estimate for the difference between two population proportions is the difference between the two sample proportions, written as:

$\hat{p}_1-\hat{p}_2$

and the standard deviation is given by

$\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}$

When np and n(1-p) is greater than 5, then the sampling distribution is approximately normal and we can use standard normal methods.

Thus, the propability of a test <span>for the difference between two population proportions is given by

$P(X\ \textless \ x)=P\left(z\ \textless \ \frac{\hat{p}_1-\hat{p}_2}{\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}} \right)$ </span>