<img src="https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20n-%5Cfrac%7B1%7D%7B6%7D%20%3D-%5Cfrac%7B1%7D%7B3%7D%20%2B%5Cfrac%7B11

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3 years ago

%7D%7B6%7D" id="TexFormula1" title="-\frac{5}{6} n-\frac{1}{6} =-\frac{1}{3} +\frac{11}{6}" alt="-\frac{5}{6} n-\frac{1}{6} =-\frac{1}{3} +\frac{11}{6}" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

mel-nik [20]3 years ago

4 0

Answer:

n = -2

Step-by-step explanation:

$\frac{-5}{6}n-\frac{1}{6}=\frac{-1}{3}+\frac{11}{6}\\\\\frac{-5}{6}n=\frac{-1}{3}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{(-1)*2}{3*2}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{-2}{6}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{-2+11+1}{6}\\\\\frac{-5}{6}n=\frac{10}{6}\\\\n=\frac{10}{6}*\frac{6}{-5}\\\\n= -2$

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elena-14-01-66 [18.8K]

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Step-by-step explanation:

The Normal distribution is a continuous probability distribution with possible values all the reals. Some properties of this distribution are:

Is symmetrical and bell shaped no matter the parameters used. Usually if X is a random variable normally distributed we write this like that:

$X \sim N(\mu , \sigma)$

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One particular case is the normal standard distribution denoted by:

$Z \sim N(0,1)$

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Oksana_A [137]

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