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FromTheMoon [43]

3 years ago

11

Karen works for 85 hours throughout a two-week period. She earns $1891.25 throughout this period . How much did Karen earn for e

ight hours of work

1 answer:

sattari [20]3 years ago

5 0

178 dollars throughout the eight hours

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Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a

vlabodo [156]

The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:

We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.

Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4

4 does not equal -8, therefore

The limit does not exist

4 0

2 years ago

How do i write b + 3 = b^2 in verbal expression

igor_vitrenko [27]

Answer:

b plus 3 is equal to b squared

7 0

3 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago

An X-ray machine for animals costs$125,000. If the loan is for 10 years, an the interest paid is $65,625, what is the interest r

Rina8888 [55]

The answer is 5.25%.

$65,625/10yrs=$6,562.50 per a year.

6,562.5/125000= .0525 which translates to 5.25%.

3 0

3 years ago

What is 505/10×10 written in unit form

Amiraneli [1.4K]

The number becomes in the unit form is a 5 hundreds and 0 tens and the 5 ones.

According to the statement

We have given that the number and the we have to write in the unit form.

So, For this purpose, we know that the

The unit form is the way to show how many of each size unit are in a number.

From the given information:

The number is a 505/10×10

Now, we have to solve this And the number becomes is

505.

And the

5 hundreds and 0 tens the 5 ones.

The unit form becomes the 5 hundreds and the 5 ones.

So, The number becomes in the unit form is a 5 hundreds and 0 tens the 5 ones.

Learn more about unit form here

brainly.com/question/2140644

#SPJ9

7 0

1 year ago