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AveGali [126]
2 years ago
5

Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5x minus 8 when x is less than 0 a

nd f of x equals absolute value -4 minus x when x is greater than or equal to 0
Mathematics
1 answer:
vlabodo [156]2 years ago
4 0
The limit does not exist. Why? Because the left hand limit DOES NOT equal the right hand limit. Let’s double check:

We could use -0.000001 to represent the left hand limit. This is less than 0. We plug in 5x - 8

5(-0.000001) - 8
-0.000005 - 8
-8.000005
If we would continue the limit (extend the zeros to infinity), we would get exactly
-8
That is our left hand limit.

Our right hand limit will be represented by 0.000001. This is greater than 0. We plug in abs(-4 - x)

abs(-4 - (0.000001))
abs(-4.000001)
4.000001
If we would continue the limit (extend the zeros to infinity), we would get exactly
4

4 does not equal -8, therefore

The limit does not exist
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In one game, the ratio of three-point baskets to three-point tries for one team was 3:8. If the team scored 27 points from three
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Since we’ve been given a ratio, 3:8, we can convert that into a fraction and form an equation from it:

\frac{3}{8} = \frac{27/3}{?}

The reason the numerator on the second fraction is 27/3 is because the team scored 27 points, not 27 baskets.

Simplify (Also replace the ? with an unknown variable):

\frac{3}{8} = \frac{9}{n}

Cross multiply:

3*n = 9*8

Simplify:

3n = 72

Divide both sides by 3:

n = 24

The team had 33 three point tries, 9 successes, and 24 fails.

-T.B.

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