Question

Which of the following is a solution of 3x2 = 7x − 3 quadratic equation

Answer 1

For this case we have the following quadratic equation:

$3x ^ 2-7x + 3 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 3\\b = -7\\c = 3$

Substituting the values we have:

$x = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (3) (3)}} {2 (3)}\\x = \frac {7 \pm \sqrt {49-36}} {6}\\x = \frac {7 \pm \sqrt {13}} {6}$

We have two roots:

$x_ {1} = \frac {7- \sqrt {13}} {6}\\x_ {2} = \frac {7+ \sqrt{13}} {6}$

ANswer:

$x_ {1} = \frac {7- \sqrt {13}} {6}\\x_ {2} = \frac {7+ \sqrt{13}} {6}$