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Reptile [31]
4 years ago
15

3r + 7r, Solve for r

Mathematics
2 answers:
Lunna [17]4 years ago
6 0
The answer is 10r you just simply add the two numbers together
sertanlavr [38]4 years ago
3 0
You can combine like terms, which means put them together.  3 plus 7 is ten, so combine them to get 10r.
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Complete the steps in solving the quadratic function 7x – 9 = 7x2 – 49x by completing the square. Fill in the blanks.
katovenus [111]

Top one is 56

-9 +  <u>112 </u>= 7(x2 - 8x + <u>16 </u>)

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Evaluate the expression.
liq [111]

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4.23076923077

Step-by-step explanation:

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Find the zeros of the function.
vlabodo [156]
The answer is 
f(x) = 9x3 + 18 x2 - 135x can be written as f(x) = x( 9x2+ 18 x - 135)
the first zero must be = 0
let's find the another zeros by solving 9x2+ 18 x - 135=0
f(-5)=135-135=0, so the answer is 
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0, -5, and 3 

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6 0
4 years ago
angle A and angle B are complementary, that is their measurements add up to 90. Angle B measures 32 more than angle A. what are
dmitriy555 [2]

<em>Complementary= 90 Degrees </em>

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A = x

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6 0
3 years ago
Read 2 more answers
Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours of production time
user100 [1]

The question is incomplete, here is the complete question

Recall the production model from Section 1.3:

Max 10x

s.t. 5x ≤ 40

x ≥ 0

Suppose the firm in this example considers a second product that has a unit profit of $5 and requires 2 hours for each unit produced. Assume total production capacity remains 40 units. Use y as the number of units of product 2 produced. . Show the mathematical model when both products are considered simultaneously.

Answer:

Max Profit: 10x + 5y

5x + 2y ≤ 40

x ≥ 0, y ≥ 0

Explanation:

x= number of units of product 1 produced

y = number of units of product 2 produced

Since the first product, x, has a unit profit of $10 and Max1 is 10x

Second product, y, has a unit profit of $5, Max2 = 5y

The maximum profit when both products are considered simultaneously is 10x + 5y

Max Profit = 10x + 5y

Time required for each unit of x is 5hours

Therefore, time required for x units is 5x hours

Time required for each unit of y is 2hours  

Therefore, time required for y units is 2y hours

Time required for the simultaneous production of both products is 5x + 2y

Since production capacity remains 40 units, 5x+2y ≤40

NB: The values of x and y cannot be negative  

5 0
3 years ago
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