Chang and Carlotta solve this problem in two different ways.
1 answer:
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Answer:
Probability of getting doubles = 1/4
Step-by-step explanation:
Given - A fair four-sided spinner has the numbers 1 to 4 marked on its sides. It is spun twice and the two scores are added together.
To find - Using a sample space diagram, find the probability of getting a double.
Proof -
Given that,
A four-sided spinner is spin twice.
So,
The Sample Space becomes
S = { (1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4) }
So,
n(S) = 16
Now,
Let A is the event Getting a double, So,
A = { (1, 1), (2, 2), (3, 3), (4, 4) }
and
n(A) = 4
So,
The Probability of getting doubles = n(A) ÷ n(S)
= 4 ÷ 16
= 1/4
∴ we get
Probability of getting doubles = 1/4
