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Brrunno [24]
3 years ago
8

Find the indicated limit, if it exists. (1 point) limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less

than 9 and f of x equals 9 minus x when x is greater than or equal to 9
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

Step-by-step explanation:

For the limit of a function to exist, then the right hand limit of the function must be equal to its left hand limit as shown;

If the function is f(x), for f(x) to exist then;

\lim_{n \to a^{+} } f(x) =  \lim_{n \to a^{-} } f(x) =  \lim_{n \to a } f(x)

Given the function;

f(x) = \left \{ {{x+9\ x

Lets check if the above statement is true.

The right hand limit of the function occurs at x> 9

f(x) = 9-x

\lim_{x \to 9+} (9-x)\\= 9-9\\= 0

The left hand limit occurs at x<9

f(x) = x+9

\lim_{x \to 9^{-} } (x+9)\\= 9+9\\= 18

From the above calculation, it can be seen that \lim_{x \to 9^{+} } f(x) \neq   \lim_{x \to 9^{-} } f(x), this shows that the function given does not exist at the given point.

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Solve by factorizing x² + 8x + 15 + 0
shusha [124]

Download

GET

Algebra

Factor

Factor the polynomial.

(

x

+

3

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(

x

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()|[]√≥

789≤

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,0.%=

Factor

x

2

+

8

x

+

15

+

0

Regroup terms.

x

2

+

0

+

8

x

+

15

Add

x

2

and

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.

x

2

+

8

x

+

15

Factor

x

2

+

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x

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using the AC method.

Tap for fewer steps...

Consider the form

x

2

+

b

x

+

c

. Find a pair of integers whose product is

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and whose sum is

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. In this case, whose product is

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.

3

,

5

Write the factored form using these integers.

(

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+

3

)

(

x

+

5

)

4 0
3 years ago
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