First we can start by finding common factors in the coefficients, 4 and 6. 4 and 6 are both divisible by 2, so we can pull this out as our first factor:
2(2p + 3pq)
Now we can look for common factors regarding p and q. Both terms include p, but only one includes q, which means we can also pull the p out as another factor:
2p(2 + 3q)
The expression inside the parentheses cannot be factored anymore, so this is the final factorisation.
No. If she selects a breakfast at random there is an equal chance she will select each item. 25% chance she will select oatmeal, 25% chance she will select cereal, 25% she will select french toast, and a 25% chance she will select scrambled eggs.
