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Tpy6a [65]
3 years ago
13

If a globe rotates through 150° in five seconds how many rotations does it make in 30 seconds ?

Mathematics
1 answer:
ANTONII [103]3 years ago
3 0
The globe will rotate 900 degrees in 30 seconds
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Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $20 and same-day tickets cost
patriot [66]

Answer:the number of advance tickets sold is 35

the number of same day tickets sold is 40

Step-by-step explanation:

Let x represent the number of advance tickets sold.

Let y represent the number of same day tickets sold.

For one performance, there were 75 tickets sold in all. This means that

x + y = 75

Advance tickets cost $20 and same-day tickets cost $25. The total amount paid for them was $1700 both tickets. This means that

20x + 25y = 1700 - - - - - - - - - - - 1

Substituting x = 75 - y into equation 1, it becomes

20(75 - y) + 25y = 1700

1500 - 20y + 25y = 1700

- 20y + 25y = 1700 - 1500

5y = 200

y = 200/5 = 40

substituting y = 40 into x = 75 - y, it becomes

x = 75 - 40

x = 35

6 0
3 years ago
Express cos B as a fraction in simplest terms.<br> 17<br> С<br> B<br> 18<br> D
klio [65]

Answer:17/18

Step-by-step explanation:

8 0
3 years ago
Are these two expressions equal? (q-r)^2 and q^2-r^2?????
Nataly_w [17]

Answer:

\boxed{\sf No}

Step-by-step explanation:

(q-r)^2

Expand brackets.

(q-r)(q-r)

q^2 -rq -rq+r^2

Combine like terms.

q^2 -2rq+r^2

The expression is not equal to q^2 -r^2.

7 0
4 years ago
Read 2 more answers
Can an obtuse triangle have a 90 degree angle?
Makovka662 [10]

Answer:

No

Step-by-step explanation:

Obtuse has an angle that is greater than 90 degrees. To be obtuse the angle must be 91 and up. Right triangles are 90-degree angles. Acute triangles have an angle that is less than 90. So, 89 and below.

I hope I answered your question correctly.

~LampteyJ

7 0
3 years ago
100 points!!! Show your work on paper
lyudmila [28]

Answer:

  • 10 cm, 15 cm

Step-by-step explanation:

Set ratios and solve for x

<u>Corresponding sides are AC with A'C' and CB with C'B'</u>

  • AC/A'C' = CB/C'B'
  • (x - 1)/2 = (x + 4)/3
  • 3(x - 1) = 2(x + 4)
  • 3x - 3 = 2x + 8
  • 3x - 2x = 8 + 3
  • x = 11

<u>Find the values of AC and CB:</u>

  • AC = x - 1 = 11 - 1 = 10 cm
  • CB = x + 4 = 11 + 4 = 15 cm
5 0
3 years ago
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