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Tatiana [17]
4 years ago
13

What are all of the solutions to x³+3x²+x-5=0.

Mathematics
1 answer:
ira [324]4 years ago
5 0

Answer:

Step-by-step explanation:

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Please solve this!
Genrish500 [490]

Answer:

I-

Step-by-step explanation:

) 5)8%2=80)4)<em>88</em><em>=</em><em>5</em><em>=</em><em>5</em><em>=</em><em>88</em><em>=</em><em><u>9</u></em><em><u>=</u></em><em><u>5</u></em><em><u>)</u></em><em><u>5</u></em><em><u>=</u></em>

5 0
3 years ago
Read 2 more answers
Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o
Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
3 years ago
Ill givee you the brainiest The graph below represent a trip taken by bicycle. Use the graph to answer questions
UkoKoshka [18]

Step-by-step explanation:

11. B - stop -horizontal line, distance does not change.

12. A - Smallest slope=smallest speed .

13. C - largest slope = fastest speed

14.Speed (at D) = 60/3 =20 km/h

15. 60 km

5 0
3 years ago
Assume there are 100 million passenger cars in the. United States and that the average fuel consumption is. 20 mi/gal of gasolin
Anastasy [175]
10,000 miles : 20 mi/gal = 500 gal
10,000 miles : 25 mi/gal = 400 gal
500 - 400 = 100 gal ( saved per year )
100 x 100,000,000 = 10,000,000,000
Answer: 10 billion gallons of fuel would be saved if the average fuel consumption mi/gal was increased to 25. 

4 0
4 years ago
SPEED QUESTION!!!
Contact [7]

Answer:

  • -6

Step-by-step explanation:

<u>Given</u>

  • 4(1 - x) + 3x = -2(x+1)

<u>Solving for x</u>

  • 4(1 - x) + 3x = -2(x+1)
  • 4 - 4x + 3x = -2x - 2
  • 4 - x = -2x - 2
  • - x + 2x = - 2 - 4
  • x = - 6
5 0
4 years ago
Read 2 more answers
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