A system of equations is graphed on the coordinate plane.

Squirrels forget where they hide about half of their nuts

Anna35 [415]

Answer:

really?

Step-by-step explanation:

3 0

3 years ago

A fair die is cast four times. Calculate

svetlana [45]

Step-by-step explanation:

<h2><em><u>You can solve this using the binomial probability formula.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows:</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) </u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008</u></em></h2><h2><em><u>You can solve this using the binomial probability formula.The fact that "obtaining at least two 6s" requires you to include cases where you would get three and four 6s as well.Then, we can set the equation as follows: P(X≥x) = ∑(k=x to n) C(n k) p^k q^(n-k) n=4, x=2, k=2when x=2 (4 2)(1/6)^2(5/6)^4-2 = 0.1157when x=3 (4 3)(1/6)^3(5/6)^4-3 = 0.0154when x=4 (4 4)(1/6)^4(5/6)^4-4 = 0.0008Add them up, and you should get 0.1319 or 13.2% (rounded to the nearest tenth)</u></em></h2>

8 0

3 years ago

Joe Popoff, a collection agent, collected 90% of a debt of $5,600.00 that had been overdue 90 days. This collection rate was 5%

sergey [27]

<span>You are given the debt collected by Joe Popoff with a 90% of a debt of $5,600.00 that had been overdue 90 days. This collection rate was 5% more than the average collection rate for that agent. The agent charged 25% commission. You are asked to find the net proceeds.

Amount collected
= $5,600 * 0.90
= $5,040

Commision
= $5,040 * 0.25
= $1,260

Net Proceeds
= $5,040 - $1,260
= $3,780 </span>

7 0

3 years ago

Express 0.64 as a fraction in lowest term? <br><br> A. 64/10<br> B.5/32<br> C.4/5<br> D.16/25

Elanso [62]

In its decimal form, it says ' 64 / 100 '.

In order to change it to its lowest terms, we look to see whether the
numerator and denominator have a common factor greater than ' 1 '.
If they do, then we can divide numerator and denominator by their
common factor, and have the same fraction in lower terms.

The common factors of 64 and 100 are 1, 2, and 4 .
We could divide top and bottom by 2, but that wouldn't finish the job.
It's always best to divide them by their <u>greatest</u> common factor, and
once you do that, you're done.

Dividing the numerator and denominator both by 4,
we get the fraction in its lowest terms:

0.64 = 64/100 = <em>16/25</em>

5 0

4 years ago

Assume a binomial probability distribution with n=55 and π=0.34 . Compute the following: (Round all your z values to 2 decimal p

Aleks04 [339]

Answer: 0.8588

Step-by-step explanation:

Assume a binomial probability distribution with n = 40 and (symbol looks like a pie sign) = 0.55.

Compute the following: (Round the value for standard deviation and intermediate calculations to 2 decimal places and your final answer to 4 decimal places.)

The mean and standard deviation of the random variable.

mean = np = 40*0.55 = 22

std = sqrt(npq) = sqrt(22*0.45) = 3.1464

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The probability that X is 25 or greater.

P(25<= x <= 40) = 1 - binomcdf(40,0.55,24) = 0.2142

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The probability that X is between 15 and 25, inclusive.

P(15<= x <=25) = binomcdf(40,0.55,25)-binomcdf(40,0.55,14) = 0.8588

7 0

4 years ago