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olga55 [171]
3 years ago
6

3.A yogurt shop offers 6 different flavors of frozen yogurt and 12 different toppings. How many choices are possible for a singl

e serving of frozen yogurt with one topping?
144
72
36
665,280

4.In how many different orders can you line up 8 cards on a table?

8
1
1,680
40,320

5.There are 10 students participating in a spelling bee. In how many ways can the students who go first and second in the bee be chosen?

1 way
90 ways
3,628,800 ways
45 ways
Mathematics
1 answer:
Sidana [21]3 years ago
4 0
<span>The correct answers are: #3) 72; #4) 40,320; #5) 90.

Explanation<span>:
#3) The number of possible choices are found by multiplying the choices of flavors and the choices of toppings:
6*12=72.

#4) The ordering of 8 cards is a permutation, given by 8!=40,320.

#5) This is a permutation of 10 objects taken 2 at a time:
P(10,2) = 10!/(10-2)!=10!/8!=90.</span></span>
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0.6(10m-5n) do you know this
DIA [1.3K]
0.6*10m=6m  0.6*5n=3n rewrite 6m-3n
hope this helps have a nice nite
5 0
3 years ago
A group of friends wants to go to the amusement park. They have $469.75 to spend on parking and admission. Parking is $10.75, an
attashe74 [19]

Answer:

12

Step-by-step explanation:

469.75-10.75 =

459 ÷ 38.25 =

12

8 0
2 years ago
99.00000000000 x 9/11
julia-pushkina [17]

Step-by-step explanation:

=99*9/11

- -

_____

=891/11

=81

3 0
3 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
In 2005, the price of a tv was $1599.00. In 2002, the price of the same type of tv has dropped to $399.00 Calculate the percent
xxTIMURxx [149]
<span>In 2005, the price of a TV was $1599.00.
In 2002, the price of the same type of tv has dropped to $399.00
Let’s Calculate the percent of decrease.
First subtract 1599 dollars with 399 dollars to know how much did the price of TV decreased.
=> 1 599 – 399 = 1 200 is the amount the decreased on TV’s price
=> 1 200 / 1599 = 0.75
=> 0.75 * 100% = 75%
Thus, the price of TV had been decreased to 25%, 75% of it were decreased</span>



3 0
3 years ago
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