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2 years ago

11

All real numbers less than or equal to -5.

2 answers:

Free_Kalibri [48]2 years ago

6 0

Answer:

|-5|=5

|-10|=10

Does this help? If it doesn't please let me know in the comments

musickatia [10]2 years ago

3 0

Answer:

<h2>-5</h2><h2>-6, -7, -8, -9, etc.</h2>

Step-by-step explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>

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Step-by-step explanation:

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$\underline{\underline{\large\bf{Given:-}}}$

$\red{\leadsto}\:$ $\textsf{}$ $\sf f(x)= x^2+6x−16$

$\underline{\underline{\large\bf{To Find:-}}}$

$\orange{\leadsto}\:$ $\textsf{ x-intercepts of the quadratic function }$ $\sf$

$\\$

$\underline{\underline{\large\bf{Solution:-}}}\\$

$\longrightarrow$ x- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.

$\begin{gathered}\\\implies\quad \sf x^2+6x−16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x^2+8x-2x −16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x(x+8)-2(x+8)=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x=2\quad or \quad x=-8 \\\end{gathered}$

$\leadsto$ x-intercepts of the given quadratic function are 2 and -8 .

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