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xxMikexx [17]
3 years ago
14

Line m passes through point (5,- 8) and has a slope - 3. What is the equation for the line

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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I need help working question 8. I don't understand how to start it
Lina20 [59]
Why don't you first try to use the cosine law to solve for an angle and then make use of the sin law to solve for the remaining angles.

Cosine law

C^2 = A^2 + B^2 - 2AB(cos C)
Solve for cos C, and then take the inverse of the trig ratio to solve for the angle.

Then set up a proportion like you have done using the sin law and solve for another angle. Knowing the sum of all angles in a triangle add up to 180 degrees, we can easily solve for the remaining angle.
8 0
3 years ago
The graph shows the height in inches, h, of a bamboo plant t months after it has been planted. Write an equation that describes
Komok [63]
Answer gonna b appl if wrong sorry
3 0
3 years ago
If A = 3x power 2+2y + 2 and B=6x power 2 - 8y + 1 then A+B and A-B​
ollegr [7]

Answer:

see explanation

Step-by-step explanation:

Given A = 3x² + 2y + 2 and B = 6x² - 8y + 1 , then

A + B

= 3x² + 2y + 2 + 6x² - 8y + 1 ← collect like terms

= 9x² - 6y + 3

-------------------------------

A - B

= 3x² + 2y + 2 - (6x² - 8y + 1) ← distribute parenthesis by - 1

= 3x² + 2y + 2 - 6x² + 8y - 1 ← collect like terms

= - 3x² + 10y + 1

5 0
3 years ago
The width of a rectangle is six meters less than three times its length. If the area of the rectangle is 105 square meters. what
Kipish [7]

Answer:

length = 7 meters

Step-by-step explanation:

l = length

w = width

w = 3×l - 6

l×w = 105 m²

l×(3×l - 6) = 105

3×l² - 6×l = 105

l² - 2×l = 35

l² - 2×l - 35 = 0

solution of a squared equation is

(-b ± sqrt(b² - 4ac))/(2a)

a = 1

b = -2

c = -35

(2 ± sqrt(4 - 4×-35))/2 = (2 ± sqrt(4+140))/2 =

(2 ± sqrt(144))/2 = (2 ± 12)/2 = 1 ± 6

l1 = 1+6 = 7 meters

l2 = 1-6 = -5 meters, which did not make any sense for an actual object.

so, l = 7 meters remains.

7 0
3 years ago
nu is designing a rectangular sandbox. the bottom is 16 square feet. which dimensions require the least amount of material for t
SCORPION-xisa [38]

Answer:

The least amount of dimensions would be using a 4ft x 4ft base.

Step-by-step explanation:

When looking to maximize area and minimize materials, a perfect square always does this. To prove the point, consider the 4 x 4 box in the answer to say a 16 x 1 box, which would have the same area.

The 4 x 4 box would have 4 sides each of 4 ft. Therefore, it would have 16 feet of sides to construct.

Meanwhile, there would be two sides on the other one that were 16 ft alone.

3 0
3 years ago
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