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murzikaleks [220]
3 years ago
6

James wants to build a wooden planter box for his garden with a volume of 100 cubic feet. If he constructed the planter with a h

eight of 2 feet and a width of 5 feet, what should the length of the planter be, in feet?
Mathematics
1 answer:
EastWind [94]3 years ago
7 0

Answer:

The length of the box is 10 feet.

Step-by-step explanation:

You have to work backwards to find volume, so just divide the volume (100) by the height (2) then divide that by the width (5) and you get your answer, 10

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-3-(-2)+(-10)<br><br> Explain answer
natka813 [3]

Answer:

-11

Step-by-step explanation:

-3-(-2)+(-10)

Two - make a pos -3+2+(-10)

-1+(-10)

-11

3 0
3 years ago
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The rectangle below has an area of 70y⁸ 30y⁶. The width of the rectangle is equal to the greatest common monomial factor of 70y⁸
Lorico [155]

Answer:

The Width of the Rectangle =10y^6

\text{Length of the Rectangle}=210y^8

Step-by-step explanation:

The area of the rectangle =70y^8 30y^6.

We are told that the width of the rectangle is equal to the greatest common monomial factor of 70y^8 \: and\: 30y^6.

Let us determine the greatest common monomial factor of 70y^8 \: and\: 30y^6.

Express each term as a product to pick out the common factors:

70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6

In the two terms, the common terms are 10 and y^6. Therefore their greatest monomial factor =10y^6

The Width of the Rectangle =10y^6

Recall: Area of a Rectangle =Length X Width

70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8

6 0
3 years ago
Read 2 more answers
A jewelry box containes 3 rings, 7 necklaces, 4 earrings, 5 braceletes and 1 tiara. If 1 piece of jewlery is selected at radom,
Brums [2.3K]

Answer:

C and D

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
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If 1=3<br><br>2=3<br><br>3=5<br><br>4=4<br><br>5=4<br><br>Then, 6=?​
anzhelika [568]
It’s 6=6 I think I hope it’s help have a nice day
8 0
3 years ago
g A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam. We ar
BaLLatris [955]

Answer:

The test statistic is z = 1.25

Step-by-step explanation:

We are interested in determining whether or not the proportion of the student who experience anxiety during the exam is significantly more than 80%.

At the null hypothesis, we test if the proportion is 80%, that is:

H_0: p = 0.8

At the alternate hypothesis, we test if the proportion is more than 80%, that is:

H_a: p > 0.8

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

80% is tested at the null hypothesis:

This means that \mu = 0.8, \sigma = \sqrt{0.2*0.8} = 0.4

A random sample of 100 students was taken. Eighty-five of the student in the sample experienced anxiety during the exam.

This means that n = 100, X = \frac{85}{100} = 0.85

The test statistic is

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.85 - 0.8}{\frac{0.4}{\sqrt{10}}}

z = 1.25

The test statistic is z = 1.25

4 0
3 years ago
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