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Vanyuwa [196]
3 years ago
15

One of the questions in the Pew Internet & American Life Project asked adults if they used the Internet, at least occasional

ly (Pew website, October 23, 2012).The results showed that 454 out of 478 adults aged 18-29 answered yes; 741 out of 833 adults aged 30-49 answered yes; and 1058 out of 1644 adults aged 50 and over answered yes.a. Develop a point estimate of the proportion of adults aged 18-29 whouse the Internet.b. Develop a point estimate of the proportion of adults aged 30-49 whouse the Internet.c. Suppose your target population of interest is that of all adults (18 yearsof age and over). Develop an estimate of the proportion of that population who use the Internet.
Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Part (a) The point estimate of the proportion of adults aged 18 to 29 who use the Internet is 0.9498.

Part (b) The point estimate of the proportion of adults aged 30 to 49 who use the Internet is 0.8896.

Part (b) Estimate of the proportion of population who use the Internet is 0.7624.

Step-by-step explanation:

Consider the provided information.

Part (a) point estimate of the proportion of adults aged 18 – 29 who use the Internet

The results showed that 454 out of 478 adults aged 18-29 answered yes;

\hat p=\frac{454}{478}=0.9498

The point estimate of the proportion of adults aged 18 to 29 who use the Internet is 0.9498.

Part (b) Develop a point estimate of the proportion of adults aged 30-49

741 out of 833 adults aged 30-49 answered yes;

\hat p=\frac{741}{833}=0.8896

The point estimate of the proportion of adults aged 30 to 49 who use the Internet is 0.8896.

Part (c) Suppose your target population of interest is that of all adults (18 years of age and over). Develop an estimate of the proportion of that population who use the Internet.

\hat p=\frac{454+741+1058}{478+833+1644}

\hat p=\frac{2253}{2955}=0.7624

Estimate of the proportion of population who use the Internet is 0.7624.

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inysia [295]

Answer:

so the correct answer is B

Step-by-step explanation:

40:5=8

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4 0
3 years ago
The First National Bank of Wilson has 700 checking account customers. A recent sample of 50 of these customers showed 29 have a
attashe74 [19]

The margin of error is 0.137 and the confidence interval for the population proportion is (0.443, 0.717).

<h3>What is the margin of error(MOE)?</h3>

It is defined as an error that provides an estimate of the percentage of errors in real statistical data.

The formula for finding the MOE:

\rm MOE = Z\times \dfrac{s}{\sqrt{n}}

Where   Z is the z-score at the confidence interval

            s is the standard deviation

            n is the number of samples.

We have:

n = 50, X = 29,

Estimate point p = 29/50 = 0.58

q = 1-p = 1-0.58 = 0.42

Z at 0.05/2 (95% confidence interval) = 1.96

\rm MOE = 1.96\sqrt{\dfrac{0.58\times0.42}{50}}

After calculating:

MOE = 0.137

Confidence interval will be: (p - MOE, p+MOE)

= (0.58-0.137, 0.58+0.137)

= (0.443, 0.717)

Thus, the margin of error is 0.137 and the confidence interval for the population proportion is (0.443, 0.717).

Learn more about the Margin of error here:

brainly.com/question/13990500

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2 years ago
If one factor of 6x^2+5x-6 is 3x-2, whats the other factor
nekit [7.7K]

Answer:

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What is 23.4 x 0.4 equals
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Draw at least six different sized rectangles that have an area of 64 square units
olga_2 [115]

Let

x------> the length of the rectangle

y------> the width of the rectangle

we know that

The area of a rectangle is equal to

A=x*y

A=64\ units^{2}

so

x*y=64 --------> equation 1

let's assume different values of x to get the different values of y

<u>case 1)</u> For x=64 units

substitute in the equation 1

x*y=64

y=64/x

y=64/64

y=1\ units      

the dimensions of the rectangle are 64 units x 1 unit

see the draw in the attached figure N 1

<u>case 2)</u> For x=32 units

substitute in the equation 1

x*y=64

y=64/x

y=64/32

y=2\ units

the dimensions of the rectangle are 32 units x 2 units

see the draw in the attached figure N 2

<u>case 3)</u> For x=16 units  

substitute in the equation 1

x*y=64

y=64/x

y=64/16

y=4\ units

the dimensions of the rectangle are 16 units x 4 units

see the draw in the attached figure N 3

<u>case 4)</u> For x=30 units

substitute in the equation 1

x*y=64      

y=64/x

y=64/30

y=\frac{32}{15} =2\frac{2}{15} \ units

the dimensions of the rectangle are 30 units x 2 (2/15) units

see the draw in the attached figure N 4

<u>case 5)</u> For x=40 units

substitute in the equation 1

x*y=64    

y=64/x

y=64/40

y=1.60\ units

the dimensions of the rectangle are 40 units x 1.60 units

see the draw in the attached figure N 5

<u>case 6)</u> For x=60 units

substitute in the equation 1

x*y=64    

y=64/x

y=64/60

y=\frac{16}{15} =1\frac{1}{15} \ units

the dimensions of the rectangle are 60 units x 1 (1/15) units

see the draw in the attached figure N 6

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3 years ago
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