Determine the eccentricity, the type of conic, and the directrix for r =2.1/1+0.7cod theta

Mathematics

1 answer:

ivolga24 [154]3 years ago

5 0

Answer:

<h2>The equation represents an ellipse with an eccentricity of 0.7.</h2>

Step-by-step explanation:

The given equation is

$r=\frac{2.1}{1+0.7cos\theta}$

This equations represents a conic section in polar form, where the coefficient of the cosine function is the eccentricity of the conic section.

So, in this case, the eccentricity is $e=0.7$ , which indicates that the equation belong to an ellipse, because the eccentricy of ellipses are between 0 and 1.

Therefore, the equation represents an ellipse with an eccentricity of 0.7.

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How many times does the equation f(x)=2x^2+9x-5 intersect the x-axis

Komok [63]

Answer:

Step-by-step explanation:

f(x)=2x^2+9x-5

When we are find how many times it intersects the x axis, we are finding the zero's. Set the equation equal to zero

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Factor the equation

0 = (2x+1) (x-5)

2*1

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2*-5 +1*1 = -9

This checks for the first last and middle terms so we factored correctly

Then using the zero product property

2x+1 = 0 and x-5 =0

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Ghella [55]

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4 years ago

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rosijanka [135]

Answer:

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Step-by-step explanation:

The formula for finding the distance between two points is this:
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The person subtracted the variables incorrectly and subtracted x1 from x2 and y1 from y2 instead of the other way around.

To correctly solve it, do this: $\sqrt{((-7-(-1))^2+(-6-2)^2} = \sqrt{(-6)^{2} + (-8)^{2} } = \sqrt{36+64} = \sqrt{100} = 10$

Hope this helped!