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3 years ago

10 + 6x + 4x = 16 – (-4)

Mathematics

2 answers:

Annette [7]3 years ago

7 0

Answer:

x=1

Hope this helps!

Jet001 [13]3 years ago

5 0

Answer:

X=1

Step-by-step explanation:

comine all like terms

10x + 10 = 16 - (-4)

10x + 10 = 20

10x=10

x=1

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Simplify.<br> (-8V2)(+1/2V32)

erastovalidia [21]

Hello!!

$\rule{300}{5}$

$\huge\blue{{\fbox{\tt{ANSWER:-\:}}}}$

$-32$

$\huge\red{{\underline{\overline{\textbf{MY\:EXPLANATION~!}}}}}$

Apply rule: $(-a) = -a$

$(-8\sqrt{2}) = - 8\sqrt{2}$

$= -8\sqrt{2}~\frac{1}{2}\sqrt{32}$

$\sqrt{2}~\sqrt{32} =\sqrt{64}$

$= -8\sqrt{64}~\frac{1}2}$

$\sqrt{64} = 8$

$= -8$ · $8$ · $\frac{1}{2}$

Multiply the numbers: $-~8$ · $8= -64$

$=-64$ · $\frac{1}{2} = -32$

$= -32$

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#LearnWithBrainly

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6 0

2 years ago

Solve the equation for h? X=r-h/y

Troyanec [42]

Answer:

h = yX -yr

Step-by-step explanation:

X=r-h/y

X - r = h/y

y*(X-r) = h

h = yX -yr

4 0

2 years ago

In the following table of values, the first differences are

ExtremeBDS [4]

Answer:

-7

Step-by-step explanation:

Given

$\begin{array}{ccc}x & {y} & {First\ difference} & {-2} & {34} & {}&{-1} & {27} & {} &{0} & {20} & {} & {1} & {13} & {} & {2} & {6} &{} \ \end{array}$

Required

The first difference

To do this, we simply calculate the difference between the consecutive y-values.

i.e.

$d = y_{n+1} - y_n$

So, we have:

$d = y_2 - y_1 = 27 - 34 = -7$

$d = y_3 - y_2 = 20 - 27 = -7$

$d = y_4 - y_3 = 13 - 20 = -7$

$d = y_5 - y_4 = 6-13 = -7$

<em>Hence, the first differences are -7 (all through)</em>

5 0

3 years ago

Last weekend, Carlos rode his bicycle for 3 hours and traveled 27 miles. On average, at what rate did Carlos travel on his bicyc

mash [69]

Carlos rode an average of 9 miles every hour on his bicycle. It is because 3*9=27 and the distance is rate multiplied by time. use the formula and check it!

Hope I helped.

Good Luck!

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3 years ago

Find all relative extrema of the function. use the second derivative test where applicable. (if an answer does not exist, enter

Alinara [238K]

The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
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The one relative extreme is a minimum at (-1.5, -3.25).

_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.

7 0

3 years ago