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LUCKY_DIMON [66]
3 years ago
8

A basketball player shoots the ball with an initial velocity of 17.1 ft/sec at an angle of 45.6 degrees with the horizontal.to t

he nearest tenth,find the initial horizontal component of the vector that represents the velocity of the ball
5.1 ft/sec
12.0 ft/sec
12.2 ft/sec
17.5 ft/sec

i got 5.1 but not sure if correct
Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0

Answer: 12.0 ft/sec

Step-by-step explanation:

<em>From the given question, we recall the following,</em>

<em>A basketball player shoots the ball with an initial velocity  = 17.1 ft/sec</em>

<em>With an angle of 45.6 degrees with the horizontal.</em>

<em>Now,</em>

<em>Let us find the initial horizontal component of the vector that represents the velocity of the ball.</em>

<em>cos θ = adjacent/hypotenuse </em>

<em>Cos 45.6 degrees = 17.1 ft/sec</em>

<em>Let find the value of x</em>

<em>x = 17.1 cos 45.6 degrees= 11.96</em>

<em>To the nearest tenth is now = 12.0 ft/sec</em>

jeka943 years ago
3 0
The horizontal component is:

17.1cos45.6≈11.96 so

vx=12.0 ft/sec  (to nearest tenth ft/s)
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