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lukranit [14]
3 years ago
10

Which values of x are point(s) of discontinuity?

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer: x= -2

x= 0

x=4

Step-by-step explanation: edge

Sloan [31]3 years ago
5 0

Answer:

x = -2

x = 0

x = 4

x = 0 and x = 4 (for the 2nd part)

Step-by-step explanation:

Edge 2020

~theLocoCoco

You might be interested in
Solve 7|3f + 4| = 91 for f. A. –29 or 312⁄3 B. 3 or –17⁄3 C. –3 or 17⁄3 D. –312⁄3 or 29
ryzh [129]

Answer:

B

Step-by-step explanation:

Given

7 | 3f + 4 | = 91 ← divide both sides by 7

| 3f + 4 | = 13

The absolute value function always returns a positive value, but the expression inside can be positive or negative. Thus there are 2 possible solutions.

Solve 3f + 4 = 13 → 3f = 13 - 4 = 9 ⇒ f = 3

Solve 3f + 4 = - 13 ⇒ 3f = - 13 - 4 = - 17 ⇒ f = - \frac{17}{3}

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

f = 3 : 7| 9 + 4| = 7| 13| = 7 × 13 = 91 ← True

f = - \frac{17}{3}

7 | - 17 + 4| = 7| - 13| = 7 × 13 = 91 ← True

Hence the correct solutions are B

4 0
4 years ago
Solve for x: 5/8=x-1/9<br><br> A. 37/8<br> B. 23/4<br> C. 11/2<br> D. 53/8
Vesna [10]

Answer:

53/72

Step-by-step explanation:

5/8 = x - 1/9

+1/9       +1/9

5/8 + 1/9 = x

9(5/8)  + 8(1/9)

45/72 + 8/72

x= 53/72

8 0
3 years ago
Can someone please help me?<br> If g(x) = x2 - 5x + 2, find g(0).
Debora [2.8K]

g(x) = x² - 5x + 2

You are looking for g(0). This means that you must replace all the x values in the equation above with 0

(0)² - 5(0) + 2

Now you need to solve according to the rules of PEMDAS:

(0)² - 5(0) + 2

0 - 5(0) + 2

0 - 0 + 2

0 + 2

2

g(0) = 2

Hope this helped!

~ Just a girl in love with Shawn Mendes

5 0
3 years ago
A 1400 kg car moving +13.7 m/s makes an elastic collision with a 3200 kg truck, initially at rest. What is the velocity of the c
Kamila [148]

Answer:

The velocity of the car after the collision is -5.36 m/s

Step-by-step explanation:

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

let the following:

m₁ = mass of the car = 1400 kg

m₂ = mass of the truck = 3200 kg

u₁ = velocity of the car before collision = 13.7 m/s

u₂ = velocity of the truck before collision = 0 m/s

v₁ = velocity of the car after collision

v₂ = velocity of the truck after collision

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

   =  [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)

   = - 5.36 m/s

So, <u>the velocity of the car after the collision is -5.36 m/s</u>

7 0
3 years ago
Pls heelp me it will mean alot to me <br>im just tryna finish high school
Rudiy27

Answer:

infinite many

Step-by-step explanation:

5 0
3 years ago
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