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vova2212 [387]
3 years ago
14

Sharon borrowed $750 at 12% for one year. She paid a $20 processing fee. How much will she pay in interest?

Mathematics
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

$90

Step-by-step explanation:

The principal amount in the loan taken by Sharon is $750 . Note hat the $20 processing fee is a one time cost and is not included in the interest calculation.

Annual Rate of interest offered to Sharon is 12%

Time interval for the loan transaction is 1 year.

So the interest for 1 year is given by \[Principal * Rate * Year /100\]

\[750 * 12 * 1 /100\] = $90

So, Sharon will have to pay $90 as interest for the loan amount $750 borrowed for one year at the rate 12%.

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Step-by-step explanation:

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3 years ago
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In the figure below ABCD is a rectangle and DA and CB are radii of circles tangent externally, AB = 4 cm. Provide the answer in
ad-work [718]

Answer:

a. Radius of DA - 2 cm.

b. Area of rectangle ABCD -

c. Area of shaded - 8-4π

d. Perimeter of shaded region - also 8-4π

<em><u>Hope this helps!  </u></em>

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3 years ago
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3241004551 [841]

Answer:

Step-by-step explanation:

At the point where two line cut across, the vertically opposite angles formed are equal. This means that

2x degrees = 78 degrees

Dividing the left hand side and the right hand side of the equation by 2, it becomes

2x/2 = 78/2

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Checking,

The sum of the angles on a straight line is 180 degrees.

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8 0
3 years ago
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Let X be a set of size 20 and A CX be of size 10. (a) How many sets B are there that satisfy A Ç B Ç X? (b) How many sets B are
Svetlanka [38]

Answer:

(a) Number of sets B given that

  • A⊆B⊆C: 2¹⁰.  (That is: A is a subset of B, B is a subset of C. B might be equal to C)
  • A⊂B⊂C: 2¹⁰ - 2.  (That is: A is a proper subset of B, B is a proper subset of C. B≠C)

(b) Number of sets B given that set A and set B are disjoint, and that set B is a subset of set X: 2²⁰ - 2¹⁰.

Step-by-step explanation:

<h3>(a)</h3>

Let x_1, x_2, \cdots, x_{20} denote the 20 elements of set X.

Let x_1, x_2, \cdots, x_{10} denote elements of set X that are also part of set A.

For set A to be a subset of set B, each element in set A must also be present in set B. In other words, set B should also contain x_1, x_2, \cdots, x_{10}.

For set B to be a subset of set C, all elements of set B also need to be in set C. In other words, all the elements of set B should come from x_1, x_2, \cdots, x_{20}.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

For each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for set B.

In case the question connected set A and B, and set B and C using the symbol ⊂ (proper subset of) instead of ⊆, A ≠ B and B ≠ C. Two possibilities will need to be eliminated: B contains all ten "maybe" elements or B contains none of the ten "maybe" elements. That leaves 2^{10} -2 = 1024 - 2 = 1022 possibilities.

<h3>(b)</h3>

Set A and set B are disjoint if none of the elements in set A are also in set B, and none of the elements in set B are in set A.

Start by considering the case when set A and set B are indeed disjoint.

\begin{array}{c|cccccccc}\text{Members of X} & x_1 & x_2 & \cdots & x_{10} & x_{11} & \cdots & x_{20}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set A?} & \text{Yes}&\text{Yes}&\cdots &\text{Yes}& \text{No} & \cdots & \text{No}\\[0.5em]\displaystyle\text{Member of}\atop\displaystyle\text{Set B?}&  \text{No}&\text{No}&\cdots &\text{No}& \text{Maybe} & \cdots & \text{Maybe}\end{array}.

Set B might be an empty set. Once again, for each element that might be in set B, there are two possibilities: either the element is in set B or it is not in set B. There are ten such elements. There are thus 2^{10} = 1024 possibilities for a set B that is disjoint with set A.

There are 20 elements in X so that's 2^{20} = 1048576 possibilities for B ⊆ X if there's no restriction on B. However, since B cannot be disjoint with set A, there's only 2^{20} - 2^{10} possibilities left.

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3 years ago
A rock drops from a height of 60m. how long does it take for it to hit the ground?
laila [671]

To solve for the time an object takes to hit the ground, the equation

<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>

(-2*60/-9.8)^½ = 3.50 seconds.

<em />

8 0
3 years ago
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