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attashe74 [19]
3 years ago
12

. >,<, = 6 × 10^−3 5 × 10^−3 Please help will mark brainly.

Mathematics
1 answer:
Wittaler [7]3 years ago
3 0

Answer:

6*10^-3  >  5*10^-3

Step-by-step explanation:

6*10^{-3}\\6*\frac{1}{10^{3} }\\6*\frac{1}{1000}\\\frac{6}{1000}=\frac{3}{500}=0.006

5*10^{-3}\\5*\frac{1}{10^{3} }\\5*\frac{1}{1000}\\\frac{5}{1000}=\frac{1}{200}=0.005

0.006>0.005, therefore, 6*10^-3>5*10^-3

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Step-by-step explanation:

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3 years ago
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Brilliant_brown [7]

Answer:

<em>Option A; the tournament did begin with 128 teams</em>

Step-by-step explanation:

We can see that this equation is represented by compound interest, in other words an exponential function, either being exponential growth or exponential decay;

f ( x ) = a + ( b )^x, where a ⇒ start value, b ⇒ constant, x ⇒ ( almost always considered ) time, but in this case rounds

Option A; The equation is given to be t ( x ) = 128 * ( 1/2 )^x. Given by the above, 128 should represent the start value, hinting that the tournament <em>did indeed begin with 128 teams</em>

Option B; As the rounds increase the number of teams approach 128. Now mind you 128 is the start value, not the end value, which would mean that <em>this statement is false</em>

Option C; The tournament began with 1/2 teams. Theoretically that would not be possible, but besides that the tournament began with 128 teams, only differed by 1/2 times as much every round. <em>This statement is thus false</em>

Option D; This situation actually represents exponential decay. If each round the number of teams differed by 1/2 times as much, the number of teams remaining is less than before, and thus this models exponential decay, not growth<em> ( statement is false )</em>

<em>Answer : Option A; the tournament did begin with 128 teams</em>

4 0
3 years ago
Laws of cosines!!! find B round to the nearest tenth!!!! second time posting this help ASAP!!!​
Nookie1986 [14]

Answer:

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Step-by-step explanation:

Use the formula for law of cosines, for this question we need so solve for angle B, so use...

b² = a² + c² - 2(a)(c)Cos B

We are given a, b, and c, so plug them in...

55² = 90² + 50² - 2(90)(50)Cos B

Now simplify...

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       0.841666667 = Cos B    (divide both sides by -9000)

       Cos^(-1) 0.841666667 = B  (use cosine inverse function on calculator)

          32.68346376° = B

           32.7° = B

 

3 0
3 years ago
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