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Olin [163]
3 years ago
13

Write the general solution to y = arcsin 0

Mathematics
1 answer:
klasskru [66]3 years ago
8 0

Answer:

Y=0

Step-by-step explanation:

Anything times 0 will always equal 0

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Margaret [11]
I think she's wrong because she the real answer is an interest rate of 6 but she's thinking wrong so she's rethink her answer I hope I helped u
7 0
4 years ago
Read 2 more answers
The graph shows which inequality???
Andreyy89
Try this option:
1. according to the line on the graph x≥0 and x<9.
2. in answers a;b;c;d;e x<0, only in answer f. √x<3, x>0. It means, that answer 'f' is correct.

answer: f.
7 0
3 years ago
The price of a skateboard, which normally sells for $50,, was decreased by 10% then decreased again by 10%, then increased by 10
AveGali [126]

Answer:

The price dropped by $5.45.

Step-by-step explanation:

    Initial price = $50.00

      Less 10 % =   -5.00

 1st sale price =   45.00

       Less 10% =    -4.50

2nd sale price =   40.50

      Plus 10 % =   +4.05

     Final price = $44.55

Change in price =   final   -  initial

                          =   44.55 - 50.00

                          = -$5.45

The price dropped by $5.45.

7 0
3 years ago
The area of a triangular flower bed in the park has an area of
blagie [28]

Answer:

b = 24 ft

h = 10 ft

Step-by-step explanation:

120 = ½hb

120 = ½h(3h - 6)

240 = h(3h - 6)

240 = 3h² - 6h

 80 = h² - 2h

    0 = h² - 2h - 80

    0 = (h - 10)(h + 8)

    h = 10 ft or -8 ft

 we ignore -8 as it makes no sense for a triangle side length.

b = 3(10) - 6 = 24 ft

8 0
2 years ago
A litter of 9 kittens available for adoption at the Humane Society has four orange kittens and five black kittens. A family come
Dovator [93]

Answer:

B

Step-by-step explanation:

What is required is the probability of selecting one orange and one black kitten.

outcomes ( 1 O and 1B) = 4C1 * 5C1

Total outcomes = 9C2

Note: the order of color does not matter it is simply a matter of selection hence only combinations are made NOT permutations.

P (1O and 1B) = outcomes ( 1 O and 1B) / Total outcomes

P (1O and 1B) = (4C1 * 5C4) / 9C2 = 0.5556

4 0
4 years ago
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