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Crazy boy [7]
4 years ago
10

How many times does 9 goes into 3000

Mathematics
2 answers:
ziro4ka [17]4 years ago
7 0
Answer=333.33

3000/9=333.33 repeating times
saveliy_v [14]4 years ago
5 0
It goes in 3000, 333.33 times.
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(3b + 12 ) divided by 2 =30 Whats is b ?
denpristay [2]

b=16 , First you multiply 30 by 2 to see what sum you need for the numerator. Then you subtract the 60 that you get by the 12 and get 48. So 3 multiplied by b should give you 48. So you just divide 48 by 3 and get 16.

6 0
4 years ago
Which of these tables represents a linear function?
IrinaK [193]

Answer:

The second table because they are almost the same thing

Step-by-step explanation:

4 0
3 years ago
Tony ought a used motorcycle. It was on sale because it would not go at high speeds. Tony was able to go 30 miles in 3/4 of an h
maxonik [38]
I believe it would be 45 miles.
4 0
3 years ago
What is the monomial if a square of a monomial is:1 9/16 a12b6
san4es73 [151]

Answer:

1\dfrac{1}{4}a^6b^3

Step-by-step explanation:

A square of a monomial is 1\dfrac{9}{16}a^{12}b^6 that is \dfrac{25}{16}a^{12}b^{6}

Use properties of exponents:

(a^m)^n=a^{mn}\\ \\\dfrac{a^m}{b^m}=\left(\dfrac{a}{b}\right)^m\\ \\a^mb^m=(ab)^m

Note that

\dfrac{25}{16}=\dfrac{5^2}{4^2}=\left(\dfrac{5}{4}\right)^2\\ \\a^{12}=a^{6\cdot 2}=(a^6)^2\\ \\b^6=b^{3\cdot 2}=(b^3)^2

Then

\dfrac{25}{16}a^{12}b^{6}=\left(\dfrac{5}{4}\right)^2\cdot (a^6)^2\cdot (b^{3})^2=\left(\dfrac{5}{4}a^6b^3\right)^2

So, the monomial is

\dfrac{5}{4}a^6b^3=1\dfrac{1}{4}a^6b^3

5 0
4 years ago
Find common ratio and series sum
Artyom0805 [142]

Answer:

Her total harvest over the

first 5 years that she owns the farm is 11277 kg

Step-by-step explanation:

Maggie is starting a small farm. In her first year, she harvests 90.000 kilograms of kale.

As she gets better at planting, fertilizing and pest control,

each year her harvest increases by 3%.

So,

In First year

She owns 90,000 kg

In Second year

She owns 90,000 kg and her harvest is increases by 3%.

i.e.,

90000 × 3 ÷ 100 = 2700

So, The increase in 90,000 kg kale is 2,700

Now,

90,000 + 2,700 = 92,700 kg

In Third year

She owns 92,700 kg and her harvest is increases by 3%.

i.e.,

92700 × 3 ÷ 100 = 2781

So, The increase in 92,700 kg kale is 2781

Now,

92,700 + 2,781 = 95,481 kg

In Fourth year

She owns 95,481 kg and her harvest is increases by 3%.

i.e.,

95481 × 3 ÷ 100 = 2846

So, The increase in 95,481 kg kale is 2846

Now,

95,481 + 2,846 = 98,345 kg

In Fifth year

She owns 98,354 kg and her harvest is increases by 3%.

i.e.,

98354 × 3 ÷ 100 = 2950

So, The increase in 98354 kg kale is 2950

Now,

98354 + 2950 = 101,295 kg

Now,

In First five years She owns

2700 + 2781 + 2846 + 2950 = 11277 kg

Thus, her total harvest over the first 5 years that she owns the farm is 11277 kg

<u>-TheUnknownScientist</u>

6 0
3 years ago
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