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3 years ago

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Choose the number sentence that illustrates the distributive property of multiplication over addition.A. 3 × (4 + 7) = (3 × 4) +

(3 × 7)B. 3 × (4 + 7) = (3 × 4) + 7C. 3 × (4 + 7) = (3 + 4) × (3 + 7) brainly

2 answers:

lutik1710 [3]3 years ago

5 0

Answer:

Option A is the answer.

Dovator [93]3 years ago

3 0

Answer:

option A 3×(4+7)=(3×4)+(3×7) IS THE ANSWER

Step-by-step explanation:

I HOPE THIS WILL HELP YOU :)

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Simplify. <br>(-6u? - 9u-4)-(-5u²+2u+3)+(2u? + 6u+4)

zheka24 [161]

Answer:

Simplified: -4u? + 5u^2 - 5u - 3

Step-by-step explanation:

8 0

3 years ago

I need help quick thanks!!!

aliya0001 [1]

Answer:

x = 1.5

Step-by-step explanation:

-1.2 (3 - x) = -1.8

<em>Apply distributive property</em>

-3.6 + 1.2x = -1.8

<em>Get 1.2x alone so add -3.6 to each side</em>

1.2x = 1.8

<em>Get x alone so divide 1.2 on each side</em>

x = 1.5

Hope this helps!

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2 years ago

The numerator and the denominator of a fraction are thirteen and fifty, respectively. When a certain number is added to this num

Talja [164]

(13 + x)/(50 - x ) = (2/1)
Cross Multiply
2(50-x) = 1(13 + x)
100 - 2x = 13 + x
add 2x to both sides
100 -2x + 2x = 13 + x + 2x
100 = 13 + 3x
Subtract 13 from both sides
100 - 13 = 13 - 13 + 3x
87 = 3x
divide both sides by 3
29 = x

(13 + 29)/(50-29) = 42/21 = 2 to 1 ratio

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3 years ago

Read 2 more answers

Round to the nearest ten-thousand <br> 568,135

DIA [1.3K]

Answer:

Step-by-step explanation:

570000 to the nearest ten thousand

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3 years ago

Let R be the relation on the set of ordered pairs of positive integers such that ((a, b), (c, d)) ∈ R if and only if ad = bc. Ar

Veseljchak [2.6K]

Answer:

The given relation R is equivalence relation.

Step-by-step explanation:

Given that:

$((a, b), (c, d))\in R$

Where $R$ is the relation on the set of ordered pairs of positive integers.

To prove, a relation R to be equivalence relation we need to prove that the relation is reflexive, symmetric and transitive.

1. First of all, let us check reflexive property:

Reflexive property means:

$\forall a \in A \Rightarrow (a,a) \in R$

Here we need to prove:

$\forall (a, b) \in A \Rightarrow ((a,b), (a,b)) \in R$

As per the given relation:

$((a,b), (a,b) ) \Rightarrow ab =ab$ which is true.

$\therefore$ R is reflexive.

2. Now, let us check symmetric property:

Symmetric property means:

$\forall \{a,b\} \in A\ if\ (a,b) \in R \Rightarrow (b,a) \in R$

Here we need to prove:

$\forall {(a, b),(c,d)} \in A \ if\ ((a,b),(c,d)) \in R \Rightarrow ((c,d),(a,b)) \in R$

As per the given relation:

$((a,b),(c,d)) \in R$ means $ad = bc$

$((c,d),(a,b)) \in R$ means $cb = da\ or\ ad =bc$

Hence true.

$\therefore$ R is symmetric.

3. R to be transitive, we need to prove:

$if ((a,b),(c,d)),((c,d),(e,f)) \in R \Rightarrow ((a,b),(e,f)) \in R$

$((a,b),(c,d)) \in R$ means $ad = cb$ .... (1)

$((c,d), (e,f)) \in R$ means $fc = ed$ ...... (2)

To prove:

To be $((a,b), (e,f)) \in R$ we need to prove: $fa = be$

Multiply (1) with (2):

$adcf = bcde\\\Rightarrow fa = be$

So, R is transitive as well.

Hence proved that R is an equivalence relation.

8 0

3 years ago