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yan [13]
4 years ago
6

PLERASE HELP I BEG YOU I REALLY NEED HELP!!!

Mathematics
1 answer:
Ann [662]4 years ago
7 0
QUESTION 1: The answers are GEOMETRIC and 256.
QUESTION 2: The answer is 3.
QUESTION 3: The answer is tn = -9n + 42
QUESTION 4: The answer is tn = 2n + 4
QUESTION 5: The answer is tn = 1*3^(n-1) (THE SECOND CHOICE)
QUESTION 6: The answer is tn = 1*(1/2)^(n-1) (THE THIRD CHOICE)
QUESTION 7: The answer is 26.
QUESTION 8: The answer is 3.

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You toss a coin 15 times. P( heads) 2/5=
PIT_PIT [208]
The answer is

2/5 = 0.4

Because

2/5 2 divide 5 = 0.4
4 0
3 years ago
Is (4,-5) a possible solution to 5x + 2y = 8?
vitfil [10]
No because x=4 and y=-5 and when you plug it in you get 5(4)+2(-5)=8 20+-10=8 and 10= does not work so it is not a possible solution.
4 0
3 years ago
Read 2 more answers
You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig
brilliants [131]

Answer:

Confidence interval

8.98-2.2\frac{1.29}{\sqrt{12}}=8.16    

8.98+2.2\frac{1.29}{\sqrt{12}}=9.80  

And the margin of error would be:

ME=2.2\frac{1.29}{\sqrt{12}}=0.819

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

\bar X= 8.98[/tex[tex]s = 1.29

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=12-1=11

The Confidence level is 0.95 or 95%, the value of significance is \alpha=0.05 and \alpha/2 =0.025, and the critical value would be t_{\alpha/2}=2.20

Repplacing the info we got:

8.98-2.2\frac{1.29}{\sqrt{12}}=8.16    

8.98+2.2\frac{1.29}{\sqrt{12}}=9.80    And the margin of error would be:

ME=2.2\frac{1.29}{\sqrt{12}}=0.819

7 0
3 years ago
What number goes on top
Sergio [31]

I'm not sure what you're really talking about.

But I think you are talking about fractions.

In fractions there are two places

The number that goes on the top is numerator.

8 0
3 years ago
The value of a car with an initial purchase price of $15,250 depreciates by 16% per year. How much is the car worth after 6 year
Scrat [10]

Answer:

$13842.43

Step-by-step explanation:

Given data

Value of car=$15,250

Rate of depreciation= 16%

Time = 6 years

We can use the exponential function below to model the value of the car after 6 years

v(t)= a(r)^x

But r= 1-0.016----------Because the value is depreciating

a=15,250  

r=0.016  

x=6

Substitute

v(t)= 15250(1-0.016)^6

v(t)=  15250(0.984)^6

v(t)=  15250*0.9077

v(t)= $13842.43

Hence the value will be $13842.43 after 6 years

8 0
3 years ago
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