solution
this is what I did. total number of ways without any restriction =900. we have to subtract the case when at least one child doesn't get any fruit. let that be C1∪C2∪C3 and we use the principle of mutual inclusion and exclusion to find that. C1∪C2∪C3=C1+C2+C3−(all two intersections)+3 intersections (no one gets a fruit case) =3⋅60−3+1=178 so case where each child gets at least one fruit =900−178=722.
Is this right, someone saying answer =49
2y(x3+9x-10x2-45) not much to be taken as a common factor
Answer:
(5 + 3y)(25 - 15y + 9y²)
Step-by-step explanation:
This is a sum of cubes and factors in general as
a³ + b³ = (a + b)(a² - ab + b²), thus
125 + 27y³
= 5³ + (3y)³ with a = 5 and b = 3y
= (5 + 3y)(5² - 5(3y) + (3y)² )
= (5 + 3y)(25 - 15y + 9y²)
The solution to inequality is less than the negative of 21. Then the correct option is C.
<h3>What is inequality?</h3>
Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The inequality is given below.
−(1/3)x + 10 > 17
Then the solution to the inequality will be
−(1/3)x + 10 > 17
−(1/3)x > 17− 10
−(1/3)x > 7
When the sign is changed then the equality sign also changed.
(1/3)x < −7
x < − 21
The value of x is less than the negative of 21.
Thus, the correct option is C.
More about the inequality link is given below.
brainly.com/question/19491153
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