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ser-zykov [4K]
4 years ago
12

Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is a

lso 53. 6f – 1 evaluated at f = 3 is 17. what is 2f + 4f + 2 – 3 evaluated at f = 3?
Mathematics
2 answers:
morpeh [17]4 years ago
6 0
We have that

the expression 2f + 4f + 2 – 3-------> we can group it   (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
Natali [406]4 years ago
4 0

Answer:

17

Step-by-step explanation:

if your on e d g e n u i t y like me, the answer is 17

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To find the distance AB across a river, a surveyor laid off a distance BC=361 m on one side of the river. It is found that B=111
zhannawk [14.2K]

Answer:

91.87m

Step-by-step explanation:

We are given that

BC=361 m

Angle B=111^{\circ}20'=111+\frac{20}{60}=111.33^{\circ}

1 degree= 60 minute

Angle C=12^{\circ} 15'=12+\frac{15}{60}=12.25^{\circ}

We have to find the value of AB.

Sum of angles of triangle=180 degrees

\angle A+\angle B+\angle C=180

\angle A=180-(\angle C+\angle B)=180-(111.33+12.25)=56.42^{\circ}

By using law of sine

\frac{AB}{sin C}=\frac{BC}{sin A}

AB=\frac{BCsin C}{sin A}=\frac{361 sin 12.25^{\circ}}{sin 56.42^{\circ}}

AB=91.87 m

7 0
4 years ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

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