All categories

2 years ago

A simple question:Is a vector made like or ?

Mathematics

1 answer:

agasfer [191]2 years ago

4 0

Answer:

A vector is a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another.

You might be interested in

1. Why does the advisor not believe the woman knocking at the town gate is a princess?

Tresset [83]

Answer:

$\pink{\rule{40pt}{555555pt}}$

Step-by-step explanation:

$\pink{\rule{40pt}{555555pt}}$

8 0

2 years ago

Help on number 19 Explain well please!!

bulgar [2K]

Answer:

48oz for $1.39

Step-by-step explanation:

if you divide 48 by 1.39 and you get 34.5323741007

if you divide 32 by .89 you get 35.9550561798

and 34.5323741007 is less than 35.9550561798 and you want the one that costs the least amount of money so you would get the Big Gulp which is 48oz for $1.39

3 0

2 years ago

How does the value of a decimal changes as you move to the left or the right in a place value chart

icang [17]

If you move it to the left the number would increase so for example you had 2.3 and you move it to the left then it would be 23, so if you times it by tenth or hundredth then it would go to the left but if you divide then it would go down so moving to the right would get you 0.23

7 0

3 years ago

Cara is hanging a poster that is 91 centimeters wide in her room. The center of the wall is 180 cm from the right end of the wal

notka56 [123]

180-91=89
89/2=44.5
each side 44.5??

7 0

2 years ago

Read 2 more answers

Messages arrive to a computer server according to a Poisson distribution with a mean rate of 11 per hour. Determine the length o

Zarrin [17]

Answer:

The length of the interval during which no messages arrive is 90 seconds long.

Step-by-step explanation:

Let X = number of messages arriving on a computer server in an hour.

The mean rate of the arrival of messages is, λ = 11/ hour.

The random variable X follows a Poisson distribution with parameter λ = 11.

The probability mass function of X is:

$P(X=x)=\frac{e^{-11}11^{x}}{x!};\ x=0,1,2,3....$

It is provided that in t hours the probability of receiving 0 messages is,

P (X = 0) = 0.76

Compute the value of t as follows:

$P(X=0)=\frac{e^{-11\times t}(11\times t)^{0}}{0!}\\0.76=e^{-11\times t}\\\ln(0.76)=-11\times t\\t=-\frac{\ln(0.76)}{11} \\=0.025\ hours\\\approx90\ seconds$

Thus, the length of the interval during which no messages arrive is 90 seconds long.

6 0

3 years ago