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OverLord2011 [107]
3 years ago
11

How do you do applications of systems

Mathematics
1 answer:
daser333 [38]3 years ago
7 0
The application system is like a test!
Example: To apply for take a walk-in exam held at the DCAS Computer Based testing and applications.
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Complete the table by filling in the elapsed tine.<br> Help pls
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Answer:

RADIUS

==================================

PROBLEM

Mary’s bicycle wheel has a circumference of 226.08 cm². What is its radius?

SOLUTION

We can solve this problem using the circumference formula in which π stands for ( 3.14 ), C stands for circumference itself and r stands for radius.

\bold{Formula \: || \: C = 2πr}Formula∣∣C=2πr

\tt{226.08 = 2(3.14) r}226.08=2(3.14)r

'Now to find the radius,Substitute 226.08 for c which is circumference in the formula.

\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}

C=2πr

226.08=2(3.14)r

6.28

226.08

=

6.28

6.28r

C=36

To check:

\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}

circumference

C=2πr

C=2(3.14)(36cm)

C=2(113.04cm)

C=226.08cm

FINAL ANSWER

If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.

\boxed{ \tt \red{r = 36}}

r=36

==================================

#CarryOnLearning

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