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OverLord2011 [107]

3 years ago

11

How do you do applications of systems

1 answer:

daser333 [38]3 years ago

7 0

The application system is like a test!
Example: To apply for take a walk-in exam held at the DCAS Computer Based testing and applications.

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Sophie and Eleanor are making bouquets using daisies and tulips. Each bouquet will have the same total number of flowers,Eleanor

Varvara68 [4.7K]

Sophie will have a greater daises to total flowers ratio than Eleanor. To make this easier to see, let's assume the boquets have 10 flowers each, and Eleanor uses 2 daisies and 8 tulips, while Sophie uses 5 daisies and 5 tulips. Then Eleanors ratio is 2:10=1:5, while Sophie's ratio is 5:10=1:2.

6 0

3 years ago

Read 2 more answers

I NEED HELP PLS ON THIS QUESTION ON MY STUDY GUIDE

matrenka [14]

Answer:

4(n + 3) = 60

Step-by-step explanation:

In the question it says '3 more than the usual' and that is a big hint that it is 4(n + 3) = 60

7 0

3 years ago

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lianna [129]

Answer:

e

Step-by-step explanation:

e

7 0

2 years ago

Find d: d= |5 1 -1 10|

alekssr [168]

Answer:

Step-by-step explanation:

8 0

2 years ago

Elimination_4x_2y=14<br> _10x+7y=_24

Gnesinka [82]

Answer:

The answer is $x=-\frac{50}{8}$ and $y=\frac{11}{2}.$

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

$-4x-2y=14$ ......(1)

$-10x+7y=-24$ ......(2)

So, we multiply the equation (1) by 7 we get:

$-28x-14y=98$

And, we multiply the equation (2) by 2 we get:

$-20x+14y=-48$

Now, adding both the new equations:

$-28x-14y+(-20x+14y)=98+(-48)$

$-28x-14y-20x+14y=98-48$

$-28x-20x-14y+14y=50$

$-8x=50$

<em>Dividing both the sides by -8 we get:</em>

$x=-\frac{50}{8}$

Now, putting the value of $x$ in equation (1):

$-4x-2y=14$

$-4(-\frac{50}{8})-2y=14$

$\frac{200}{8} -2y=14$

$25-2y=14$

<em>Subtracting both sides by 25 we get:</em>

$-2y=-11$

<em>Dividing both sides by -2 we get:</em>

$y=\frac{11}{2}$

Therefore, the answer is $x=-\frac{50}{8}$ and $y=\frac{11}{2}.$

5 0

3 years ago