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Yanka [14]
4 years ago
12

Please help me!! Will mark brainliest!!

Mathematics
2 answers:
Brut [27]4 years ago
8 0

Answer:

its D

Step-by-step explanation:

Bas_tet [7]4 years ago
6 0

Answer:

D

Step-by-step explanation:

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Number 1 And 3 both represent odd functions. Please mark brainliest
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3 years ago
If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
harina [27]

Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0
4 years ago
What is x (its a parralleligram)
creativ13 [48]

Check the picture below.

7 0
3 years ago
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