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kirill [66]
3 years ago
11

Plz help me I don't know how to do this!!!!

Mathematics
1 answer:
m_a_m_a [10]3 years ago
8 0

Answer:

x = 25

Step-by-step explanation:

Since it is an equilateral triangle it means that all the sides are 50. Each side is equal so, if you divide 150 by 3 you get 50. (and since perimeter is the adding of each side)

Now you want to try to figure out what the altitude is of the triangle so you divide it in half. Making the bottom side length now 25 because half of 50 is 25. You now have to use Pythagoreans theorem to figure out the altitude:

c^2 - a^2 = b^2

50^2 - 25^2 = b^2

2500 - 625 = b^2

1875 = b^2

√1875 = b

43.30127019

now you put that into the expression: x√3:

x√3 = 43.30127019

x = (43.30127019) ÷ (√3)

x = 25

Hope this helped!

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Virty [35]

standard from Ax +By = C

y = 4x+10

subtract 4x from each side

-4x+y = 10

or 4x - y = -10

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3 years ago
The mean number of words per minute (WPM) read by sixth graders is 86 with a variance of 225. If 44 sixth graders are randomly s
Dmitry [639]

P(X<=x) = 1 + 5.486 = 6.486

The z-score of the information given is,

z = (x - µ )/ σ

Where,

µ = mean

σ = standard deviation

From the information given,

x = 3.71

µ = 86

σ  = √225 = 15

hence,

z = (3.71 - 86)/15 = -5.486

thus,

P(X<=x) = 1 + 5.486 = 6.486

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2 years ago
in the bag, there are certain number of toy- blocks with alphabets A,B,C and D written on them. The ratio of blocks A:B:C:D is 4
Svet_ta [14]
Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1

Let us consider the common ratio to be ‘x’.

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toy blocks with alphabet C is 3x and

toy blocks with alphabet D is x


Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.

As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.

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350 is the required number.
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3 years ago
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The amount of money spent on textbooks per year for students is approximately normal.
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Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

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When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

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The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

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     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

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Answer:

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