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jeka57 [31]
3 years ago
5

How do you find the answer y and what is the answer?

Mathematics
1 answer:
konstantin123 [22]3 years ago
3 0
 i think an estimate for the answer would be around 90 degrees
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Find the slope of a line parallel to this given line
dybincka [34]

bearing in mind that parallel lines have the same exact slope, then any parallel line to the one above will have the same slope as that one.

\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \qquad \implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{7}{3}}x-4

3 0
3 years ago
Identify the slope and y intercept of the line having equation y=-8x-15
Harrizon [31]

Answer: the slope would be a negative slope with -15 as the y intercept.

Step-by-step explanation:

3 0
2 years ago
Why is 8.8 a rational number
disa [49]

Answer:

See below

Step-by-step explanation:

8 is classified as a rational number because it can be made into a fraction. 8.8 = 8 8/10 = 88/10

5 0
3 years ago
Please help me solve this
andrew-mc [135]

A function assigns the values. The value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

Given p(x)= x²+5x, therefore, the value of (p·p)(x) can be written as,

(p·p)(x) = p(p(x))

            = (x²+5x)²+5(x²+5x)

            = x⁴ + 25x² + 10x³ + 5x² + 25x

            = x⁴ + 10x³ + 30x² + 25x

Hence, the value of (p·p)(x) is x⁴ + 10x³ + 30x² + 25x.

Learn more about Function:

brainly.com/question/5245372

#SPJ1

4 0
2 years ago
Simplify 2- 5/8 and -2 3/5 A. -6 33/40 B. 4- 3/8 C. 4 3/8 d. 6 33/40
worty [1.4K]

Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction.

-2\dfrac{5}{8}*(-2\dfrac{3}{5})=\dfrac{-21}{8}*\dfrac{-13}{5}\\

                    =\dfrac{(-21)*(-13)}{8*5}\\\\\\=\dfrac{273}{40}\\\\=6\dfrac{33}{40}

4 0
2 years ago
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