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3 years ago

13

HELLPPPPPPP ASAPPPP PLEASEEEE

1 answer:

avanturin [10]3 years ago

3 0

Answer:

2. f(-7)= -3(-7)-2

21-2

=19

10. h(1)= | 1-7(1) |

|-6|

=6

11. h(-7) =|1-7(-7)|

|1-49|

|-48|

=48

12. [23-h(9) =|1-7(-9)|]

h(9) =|1-7(9)|

|-62|

23-62

=39

Step-by-step explanation:

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23, 34, 27, 7, 30, 26, 28, 31, 34 What number is an outlier for the given data? A) 7 B) 23 C) 31 D) 34

marin [14]

An outlier for a data set is a number which stands out, meaning it is not close to the rest of the numbers. It can either be greater OR less than the rest of the numbers.

<span>23, 34, 27, 7, 30, 26, 28, 31, 34

Which number stands out from this data set?

Yep! 7. This is because it is not close to the other numbers, whereas the other numbers are closer to each other.

A) 7.</span>

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5x-4%2B2%28x-4%29%3D16" id="TexFormula1" title="5x-4+2(x-4)=16" alt="5x-4+2(x-4)=16" align="ab

mariarad [96]

Answer:

$\boxed{x = 4}$

Step-by-step explanation:

=> 5x-4+2(x-4) = 16

Expanding the brackets

=> 5x-4+2x-8 = 16

Combining like terms

=> 5x+2x-4-8 = 16

=> 7x - 12 = 16

Adding 12 to both sides

=> 7x = 16+12

=> 7x = 28

Dividing both sides by 7

=> x = 4

3 0

3 years ago

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Need help pick 3 right answers .?

deff fn [24]

Answer:

A, B, & D

Step-by-step explanation:

Because they all have equal signs

6 0

3 years ago

What is the answer 47 * 63

Anuta_ua [19.1K]

<h3>47 × 63 = <u>2961</u></h3>

<h3>... Hope this will help... </h3>

<h3>U can also verify the answer using a calculator </h3>

8 0

2 years ago

Find the line through

Kaylis [27]

Answer:

$(\frac{1}{2},\frac{-1}{2},\frac{1}{2})$

Step-by-step explanation:

We have been given the intersection coordinates:

(7,1,-6) and perpendicular to the line x=-1+t ,y=-2+t and z=-1+t

From the condition of perpendicularity we know:

$(7,1,-6)(x,y,z)$

$\Rightarrow 7x+y-6z=0$

Now, we have given x=-1+t , y=-2+t and z= -1+t

$7(-1+t)+(-2+t)-6(-1+t)=0$

$-7+7t-2+t+6-6t=0$

$\Rightarrow -3+2t=0$

$2t=3$

$t=\frac{3}{2}$

Now, substituting t in the given coordinates x,y and z we get:

$x=-1+\frac{3}{2}=\frac{1}{2}$

$y=-2+\frac{3}{2}=\frac{-1}{2}$

And $z=-1+\frac{3}{2}=\frac{1}{2}$

3 0

3 years ago

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