1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pochemuha
3 years ago
6

3.9+1.2 whats the answer

Mathematics
2 answers:
S_A_V [24]3 years ago
7 0
5.1 always put the bigger number on top
LenKa [72]3 years ago
4 0

Answer:

it's answer is 5.1

Step-by-step explanation:

3.9 + 1.2

= 5.1

You might be interested in
PLEASE HELP ME WITH THIS QUESTION I AM OFFERING A LOT OF POINTS BUT I HAVE NO IDEA WHAT THIS QUESTION IS!!!!!!
Aloiza [94]

Answer: I think b

Step-by-step explanation: I had the same question

5 0
3 years ago
For each of the following​ situations, indicate what the general impact on the Type II error probability will​ be:
Paraphin [41]

Answer:

Step-by-step explanation:

Hello!

The type II error is committed when you fail to reject a false null hypothesis.

The probability associated with this type of error is symbolized as β.

a. The alpha level is increased.

α and β are two probabilities that are closely related in such a way that if alpha is decreased, beta automatically increases and vice versa when the sample size n is predetermined.

If you increase α then the probability of committing type II error (β) decreases.

b. The "true" population mean is moved farther from the hypothesized population mean.

If the true population mean is moved away from its hypothesized value, then the probabilities of "keeping" a false null hypothesis are bigger.

c. The alpha level is decreased.

This is the inverse situation from a. If you decrease α then, β is automatically increased.

d. The sample size is increased.

If the sample size "n" is left free, it can be shown that by increasing the sample size, both α and β decrease. In practice, α is fixed and β is calculated with several possible sizes of n. Finally choosing as sample size the one that minimizes or gives a reasonable value of β.

I hope it helps!

3 0
3 years ago
A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The
zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200,  300

Let X be the total refund payment on the seven day cruise.

We can say  X = 0, if there is no rain on all 7 days.

P(X = 0) = _nC_x * P^x * (1 - P)n-x

P(X = 0) =  _7C_o * 0.2^0 * (1-0.2)^{7-0

P(X = 0) =1 * 1* (1-0.2)^{7

P(X = 0) =(0.8)^{7

P(X = 0) =0.2097152

If it rains on any one day; then X = 100

P(X = 100) = _nC_x * P^x * (1 - P)n-x

P(X = 100) =  _7C_1 * 0.2^1 * (1-0.2)^{7-1

P(X = 0) =7 * 0.2* (1-0.2)^{6

P(X = 100) =7* 0.2* (0.8)^{6

P(X = 100) =0.3670016

if it rains on any two day  ; then X = 200

P(X = 200) = _nC_x * P^x * (1 - P)n-x

P(X = 200) =  _7C_2 * 0.2^2 * (1-0.2)^{7-2

P(X = 200) =  21 * 0.2^2 * (0.8)^{5

P(X = 200) = 0.2752512

if it rains on any three day or more than that ; then X = 300

P(X \ge 300) = 1 - P(X < 300)  \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple[Var X] =E [X^2] - (E [X])^2

where;

E[X^2]  = \sum x^2 \times p \\ \\ E[X^2]  = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\  E[X^2]  = 0  + 3670.016 + 11010.048+ 13322.88  \\ \\  E[X^2]  =28002.944

(E [X]) = \sum x * p\\ \\  (E [X]) =  0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0
3 years ago
Which rule represents the translation of hexagon D'E'F'G'H'I' ?
Sveta_85 [38]

Answer:

C (X,Y)->(X-4,×-5) I would say bro

3 0
3 years ago
What is the distributive property for 9−12x+6y=
Ulleksa [173]

Because there are no parentheses, I'm assuming you're asking for how to factor this using the GCF, which can be done like so:

9−12x+6y

Factor a 3 out of this expression.

3(3 - 4x + 2y)

The expression has been simplified using the distributive property in reverse.


8 0
3 years ago
Other questions:
  • If n represents a number in the following sequence, the next term in the sequence can be determined by using which of the follow
    7·2 answers
  • What is the distance between the points (–4, 2) and (3, –5)?
    6·2 answers
  • What is (1/2)^2 x 1/2 x (1/2)^3
    10·1 answer
  • Simply (2x^-3 y^5) (-4x^8 y^2)
    14·1 answer
  • What is the connection between rational exponents and radicals?
    13·2 answers
  • Where are the negative rational numbers placed on a vertical number line?
    12·2 answers
  • The answer of how to do the question
    5·1 answer
  • Find m congruent to S
    10·2 answers
  • Justin is 2years older than one third Marcellas age. Aimee is four years younger than 2 times Justin's age. Define a variable an
    5·1 answer
  • Please please help me
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!