Volume of cylinder
v = πr²
v = 22/7 x 21²
v = 1385.441 cm³
the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Based on the lengths of the given triangles and the length of segment BD, the length of segment AD is 22.20.
<h3>What is the length of segment AD?</h3>
The triangle ABC is a right angled triangle with segment AB being the hypothenuse.
We can therefore find this length using the Pythagoras Rule:
Hypothenuse ² = a² + b²
Hypothenuse ² = 28.6² + 23.2²
Hypothenuse ² = 1,356.20
Hypothenuse = √1,356.20
= 36.83
Length of AD:
= AB - BD
= 36.83 - 14.60
= 22.2
Find out more on the Pythagorean theorem at brainly.com/question/343682.
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Answer:
i think that is 147
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