Answer:
b||c; c||d; b||d
Step-by-step explanation:
Substituting 10 for x, in the angle beside b we have
7(10)-5 = 70-5 = 65
In the angle beside c we have
10(10)+15 = 100+15 = 115
In the angle beside d we have
12(10)-5 = 120-5 = 115
In the angle beside we have
8(10)-25 = 80-25 = 55
The angle beside c has a vertical angle on the other side of c. This angle would be same-side interior angles with the angle beside b; this is because they are inside the block of lines made by b and c and on the same side of a, the transversal. These two angles are supplementary; this is because 65+115 = 180. Since these angles are supplementary, this means that b||c.
The angle beside c and the angle beside d would be alternate interior angles; this is because they are inside the block of lines made by c and d and on opposite sides of the transversal. These two angles are congruent; this means that c||d.
Since b||c and c||d, by the transitive property, b||d.
Answer:
One million, two hundred eighty-nine thousand, three hundred four.
Step-by-step explanation:
In the figure attached, red circle A and red point B are the circle and external point of interest. Note that we must know where the center of circle A is. If we don't know that, there are construction techniques for finding it, but that is beyond the scope of this answer.
Step 1. Set your compass to a radius greater than half the length of segment AB. Here, we have made the radius AD.
Step 2. Draw arcs above and below the center of segment AB centered at A and B using the radius of Step 1. Here the "arc" is shown a a full (green) circle. Only the points where the arcs intersect (E and F) are of interest, so it is not necessary to draw the full circle.
Step 3. Identify the points of interesection (E and F) of the arcs of Step 2, then draw a line segment between them. This segment (EF) is the perpendicular bisector of AB. Mark point G where it intersects segment AB. As with the green circles, it is not necessary to draw the whole line EF, since we are only interested in the location of the midpoint of AB, which is point G.
Step 4. Using G as the center, and GA or GB as the radius, draw semicircle AHB. The point of intersection H is the only part of that (blue) circle of interest, so it is not necessary to draw the whole thing.
Step 5. Finish the consruction by drawing tangent line BH.
26 because it is a lot bigger than all of the other numbers
A number a lot lower than all the other numbers could work too but not in this case