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posledela
3 years ago
8

I have 4 ounces. how many pounds do i have ?

Mathematics
2 answers:
Gala2k [10]3 years ago
3 0

Answer:

0.25 pounds

Step-by-step explanation: there are 16 ounces in a pound

Alenkinab [10]3 years ago
3 0

Answer:

.25 lbs

Step-by-step explanation:

1 pound is 16 ounces

4 ounces * 1 lbs/16 ounces

4/16 lbs

.25 lbs

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What is the decibel level of a dog barking with intensity 10−5 watts per square inch? Use a logarithmic model to solve.
Vsevolod [243]

Answer:

The sound intensity is about 101.9 dB

Step-by-step explanation:

Sound intensity is the amount of sound energy per unit area.

The intensity of the dog bark is 10⁻⁵ W/in². The intensity of sound in decibels is given by:

\beta=10\ dB*log(\frac{I}{I_o} )\\\\Where\ I=Sound\ intensity\ in \ W/m^2, I_o=reference\ sound\ intensity=10^{-12}\ W/m^2\, \beta= sound\ intensity\ in\ dB

I = 10⁻⁵ W/in² = 0.0155 W/m²

Therefore:

\beta=10\ dB*log(\frac{I}{I_o} )\\\\\beta=10\ dB*log(\frac{0.0155}{10^{-12}} )\\\\\beta=101.9\ dB

The sound intensity is about 101.9 dB

5 0
3 years ago
The weight distribution of parcels sent in a certain manner is normal with mean value 15 lb and standard deviation 3.3 lb. The p
disa [49]

Answer: 23.7 lb

Step-by-step explanation:

Mean m = 15 lb

Standard deviation d = 3.3 lb

To determine the surcharge weight, we need to know the highest weight of 99% of the parcels.

P(z<x) = 0.99 = ¢(Z)

Z = 2.33

Since Z = (x - m)/d

x = dZ + m

x = 3.3*2.33 + 15

x = 22.689 lb approximately

x = 22.7 lb

Therefore, the highest weight for 99% if the parcels is 22.7 lb.

That is, the surcharge weight = 22.7 + 1 = 23.7 lb

3 0
3 years ago
HELP ASAP. WILL GIVE BRAINLIEST.
faust18 [17]

Answer:

because they had to simplify the problem first

Step-by-step explanation:

4 0
3 years ago
The height of the triangle is
blsea [12.9K]

Answer:height:12

Base:25

Area:150 cm2

Step-by-step explanation:

4 0
3 years ago
Solve for $2\left(1-\frac{1}{2}\right)+3\left(1-\frac{1}{3}\right)+4\left(1-\frac{1}{4}\right)+\ldots
Elina [12.6K]

Answer:

$2\left(1-\frac{1}{2}\right)+3\left(1-\frac{1}{3}\right)+4\left(1-\frac{1}{4}\right)+\ldots+10\left(1-\frac{1}{10}\right)=?$

2(\frac{2}{2} -\frac{1}{2} )+3(\frac{3}{3} -\frac{1}{3} )+4(\frac{4}{4} -\frac{1}{4} )+5(\frac{5}{5} -\frac{1}{5} )+6(\frac{6}{6}-\frac{1}{6}  )+7(\frac{7}{7}-\frac{1}{7} )+8(\frac{8}{8} -\frac{1}{8}  )+9(\frac{9}{9} -\frac{1}{9} )+10(\frac{10}{10} -\frac{1}{10} )\\\\=2(\frac{1}{2}) +3(\frac{2}{3})+4(\frac{3}{4})+5(\frac{4}{5})  +6(\frac{5}{6})  +7(\frac{6}{7})  +8(\frac{7}{8})  +9(\frac{8}{9})  +10(\frac{9}{10})\\\\=1+2+3+4+5+6+7+8+9\\\\=45

3 0
3 years ago
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