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AleksAgata [21]
3 years ago
12

How do I do this? Please help!

Mathematics
1 answer:
lakkis [162]3 years ago
6 0
C
you have to find the area Length* width then divide it by the total amount
42x25.5=1071
1071/ 771.12=1.39
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15 points PLEASE HELP!!!<br><br> Factor the following equation:<br> <img src="https://tex.z-dn.net/?f=x%5E2%2B3x%2B4" id="TexFor
ycow [4]

Step-by-step explanation:

x²+3x+4=0

x²+3x_ +2=0

x²+3x_2=-2

x²+3x_2+(3x_4)²=-2+(3/4)²

(x+3/4) =-2+9_16

x+3_4 = -32+9__16 =√-23_6

x+3_4 =-√23_4

x = -3+√-23___4

x = -3- √-23___4 , -3+√-23___4 //

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5 0
3 years ago
What is x-31=112<br><br><br>please help​
Oliga [24]

Answer:

143

Step-by-step explanation:

x-31=112

Add 31 to both sides,

x - 31 = 112

  +31    +31

-31 and +31, cancel out so we're left with...

x = 143

5 0
3 years ago
Read 2 more answers
8th grade geometry-- will give 15 pts+ brainliest!!!!!!!!!!!! For this question i put reflection over the y axis, reflection ove
Alla [95]

Answer:

you also have to translate 3 units to the right

Step-by-step explanation:

when you finished your reflections the coordinate of the point is (1, -1) while it should be (4, -4), that means you not only need to move it by 3 down but also to the right.

4 0
2 years ago
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A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

3 0
3 years ago
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I need help pleasee thank
Ganezh [65]

Answer:

A=51

a=22.2

c=28.6

Step-by-step explanation:

∠A=180-90-39

     =51

a/sin51=18/sin39

a=22.2

c/sin90=18/sin39

c=28.6

4 0
3 years ago
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