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3 years ago

Last month, Justina dog ate 50 cans of dog food in 30 days. How many cans should Justin buy for the next 6 days

Mathematics

1 answer:

natali 33 [55]3 years ago

7 0

Answer:

The answer is 7 2/3 cans for the next 6 days.

Step-by-step explanation:

Given: The dog ate 50 cans in 30 days.

To get how many cans per day, divide:

50/30 = 1 2/3 cans per day.

To get how many cans for 6 days, multiply:

6 * 1 2/3 = 18/3 + 5/3 = 23/3 = 7 2/3 cans or 7.667 in decimal form.

Hope this helps!! Have an Awesome day!!! :-)

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The average density of the material in intergalactic space is approximately 2.5 × 10–27 kg/m3. what is the volume of a lead samp

Lesechka [4]

Answer:

e. $1.8\times 10^{-6}m^3$

Step-by-step explanation:

It is given that,

The density of intergalactic space material is $2.5 \times 10^{-27}$ kg per cubic meter.

And the volume of intergalactic space material is $8.0\times 10^{24} m^3$

So the mass of that much intergalactic space material is,

$m= \rho\times v$ , where 'm' is the mass, and 'v' is the volume.

Putting the values we get,

$m=2.5 \times 10^{-27}\times 8.0 \times 10^{24}$

$m=20\times 10^{(-27+24)}=20\times 10^{-3} kg$

It is also given that the mass of lead is the same as the mass of the intergalactic space material. Therefore, the mass of lead is $20 \times 10^{-3}=2 \times 10^{-2}kg$

So the volume of lead is,

$v=\frac{m}{\rho} =\frac{2 \times 10^{-2}}{11300} = 0.00000177 m^3$

$v=1.77 \times 10^{-6}=1.8\times 10^{-6}m^3$

So the volume of lead is $v=1.8\times 10^{-6}m^3$ .

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3 years ago

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Firdavs [7]

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3 years ago

A5cm x 11 cm rectangle sits inside a circle with radius of 12 cm.

never [62]

Answer:

397.16 cm²

Step-by-step explanation:

Area of the circle = πr²

3.14 * 144 = 452.16

452.16 - (11 x 5 ) = area shaded region

452.16 - 55 = 397.16

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

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Vitek1552 [10]

Answer:

a > m/bp

Step-by-step explanation:

flip the equation

abp > m

divide both sides with bp

abp/bp > m/bp

a > m/bp

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3 years ago

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